yes
No. Spherical geometry did not disprove Euclidean geometry but demonstrated that more than one geometries were possible. Different circumstances required different geometries. Similarly hyperbolic geometry did not disprove either of the others.
i have no idea lol
No, both spherical and hyperbolic geometries are noneuclidian.
False.
Lobachevsky's work did not create spherical geometry; rather, he is known for developing hyperbolic geometry, which deviates from Euclidean principles. Spherical geometry, on the other hand, is based on the properties of figures on the surface of a sphere and includes concepts such as great circles and the sum of angles in a triangle exceeding 180 degrees. Both geometries are non-Euclidean, but they arise from different fundamental assumptions about space. Lobachevsky's contributions helped to expand the understanding of non-Euclidean geometries, including both hyperbolic and spherical forms.
Geometry that is not on a plane, like spherical geometry
No. Spherical geometry did not disprove Euclidean geometry but demonstrated that more than one geometries were possible. Different circumstances required different geometries. Similarly hyperbolic geometry did not disprove either of the others.
No.
Geometry that is not on a plane, like spherical geometry
i have no idea lol
No, both spherical and hyperbolic geometries are noneuclidian.
In Euclidean geometry, parallels never meet. In other geometry, such as spherical geometry, this is not true.
False.
Spherical
Euclidean geometry, non euclidean geometry. Plane geometry. Three dimensional geometry to name but a few
In Euclidean plane geometry, two lines which are perpendicular not only can but must intersect. (I believe the same is true for elliptic geometry and hyperbolic geometry.)
In Euclidean plane geometry, two lines which are perpendicular not only can but must intersect. (I believe the same is true for elliptic geometry and hyperbolic geometry.)