Other than what? It really all depends on what is given. For example:
Let the diagonals be x+5 and x:- If: 0.5*(x+5)*x = 150 sq cm Then: x2+5x-300 = 0 Solving the above by means of the quadratic equation formula: x = +15 Therefore: diagonals are 15 cm and 20 cm The rhombus has 4 interior right angle triangles each having an hypotenuse Dimensions of their sides: 7.5 and 10 cm Using Pythagoras' theorem: 7.52+102 = 156.25 Its square root: 12.5 cm Thus: 4*12.5 = 50 cm which is the perimeter of the rhombus Note: area of any quadrilateral whose diagonals are perpendicular is 0.5*product of their diagonals
It is important to know several techniques for solving equations and inequalities because one may work better than another in a particular situation.
Providing that it is a regular polygon then let its sides be x: So: 0.5*(x2-3x) = 464 diagonals Then: x2-3x-928 = 0 Solving the equation: x = 32 sides Total sum of interior angles: 30*180 = 5400 degrees Each interior angle: (5400+360)/180 = 168.75 degrees
In a two step equation, you need to do another step.
What role of operations that applies when you are solving an equation does not apply when your solving an inequality?"
yes. there are certain formulae for solving them. dont remember
Let the number of sides be x and by solving the equation for diagonals 0.5(x*x-3x) = 135 the solution is -15 or 18 and so therefore it has 18 sides irrespective if it is an irregular or a regular polygon
Let the sides be n and use the formula for the diagonals of a polygon:- If: 0.5*(n^2 -3n) = 90 Then: n^2 -3n -180 = 0 Solving the above quadratic equation: n = -12 or n = 15 Therefore the polygon has 15 sides
A decagon. Proof: In an n sided polygon, each vertex would be have (n-3) diagonals attached to it, as it would be connected to every vertex other than itself and the two next to it by a diagonal. There are n sides, so there are n(n-3) ends of diagonals. Therefore there are (n(n-3))/2 diagonals in the polygon. Taking the number of diagonals to be 35, we have: (n(n-3))/2 = 35 n(n-3) = 70 which gives the quadratic n2-3n-70 = 0 Solving this gives n = 10 and -7. -7 can be ignored, so the answer is 10.
Formula: 0.5*(n2-3n) = diagonals whereas n is the number of sides So if: 0.5*(n2-3n) = 54 Then: n2-3n-108 = 0 Solving the above quadratic equation gives n a value of -9 and 12 It has to be 12 which means it is a dodecagon polygon
Its a algorithm. DPLL/Davis-Putnam-Logemann-Loveland algorithm is a complete, backtracking-based algorithm for deciding the satisfiability of propositional logic formulae in conjunctive normal form, i.e. for solving the CNF-SAT problem.
The formula to calculate the number of diagonals in a polygon is n(n-3)/2, where n represents the number of vertices. Setting this formula equal to 560 and solving for n, we get n(n-3)/2 = 560. By solving this quadratic equation, we find that the polygon has 20 vertices.
Decision making, also referred to as problem solving
Let n be the number of sides: 1/2*(n2-3n) = diagonals 1/2*(n2-3n) = 902 Multiply both sides by 2 and form a quadratic equation: n2-3n-1804 = 0 Solving the above by means of the quadratic equation formula gives a positive value for n as 44 Therefore the polygon has 44 sides
Engineering would be the first profession that comes to mind where the definition of the profession is problem solving. Computer science would be another one.
Let the diagonals be x+5 and x:- If: 0.5*(x+5)*x = 150 sq cm Then: x2+5x-300 = 0 Solving the above by means of the quadratic equation formula: x = +15 Therefore: diagonals are 15 cm and 20 cm The rhombus has 4 interior right angle triangles each having an hypotenuse Dimensions of their sides: 7.5 and 10 cm Using Pythagoras' theorem: 7.52+102 = 156.25 Its square root: 12.5 cm Thus: 4*12.5 = 50 cm which is the perimeter of the rhombus Note: area of any quadrilateral whose diagonals are perpendicular is 0.5*product of their diagonals
Like weight lifting is to muscle development