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Other than what? It really all depends on what is given. For example:
- If you know the length of one diagonal, the other is just as long.
- If you know the length and width of the rectangle, use Pythagoras' formula for the diagonal.
- If you know one of the sides of the rectangle, and an angle, use some basic trigonometry to find the diagonal.
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What is the perimeter of a rhombus when one of its diagonals is greater than the other diagonal by 5 cm with an area of 150 square cm showing key aspects of work?
Let the diagonals be x+5 and x:- If: 0.5*(x+5)*x = 150 sq cm Then: x2+5x-300 = 0 Solving the above by means of the quadratic equation formula: x = +15 Therefore: diagonals are 15 cm and 20 cm The rhombus has 4 interior right angle triangles each having an hypotenuse Dimensions of their sides: 7.5 and 10 cm Using Pythagoras' theorem: 7.52+102 = 156.25 Its square root: 12.5 cm Thus: 4*12.5 = 50 cm which is the perimeter of the rhombus Note: area of any quadrilateral whose diagonals are perpendicular is 0.5*product of their diagonals
Why is it important to know various techniques for solving systems of equations and inequalities?
It is important to know several techniques for solving equations and inequalities because one may work better than another in a particular situation.
What is the size of each individual interior angle of a polygon having 464 diagonals showing key stages of work?
Providing that it is a regular polygon then let its sides be x: So: 0.5*(x2-3x) = 464 diagonals Then: x2-3x-928 = 0 Solving the equation: x = 32 sides Total sum of interior angles: 30*180 = 5400 degrees Each interior angle: (5400+360)/180 = 168.75 degrees
How is solving a two step equation different from one step equations?
In a two step equation, you need to do another step.
What role of operations that applies when you are solving an equation does not apply when your solving an inequality?
What role of operations that applies when you are solving an equation does not apply when your solving an inequality?"
