29
The diagonal is 14.21 cm
Area = 0.5*(9 + 3)*11 = 0.5*12*11 = 66 sq cm
Dimensions are given out as length by width 14cm by 1cm 13cm by 2cm 12cm by 3cm 11cm by 4cm 10cm by 5cm 9cm by 6cm 8cm by 7cm And the rest is all repeats of the above.
53.5 square cm to 1 d.p. Use the cosine rule to find an angle. Then use: Area = 1/2*a*b*sin C
29
The diagonal is 14.21 cm
Area = 0.5*(9 + 3)*11 = 0.5*12*11 = 66 sq cm
Dimensions are given out as length by width 14cm by 1cm 13cm by 2cm 12cm by 3cm 11cm by 4cm 10cm by 5cm 9cm by 6cm 8cm by 7cm And the rest is all repeats of the above.
11cm
53.5 square cm to 1 d.p. Use the cosine rule to find an angle. Then use: Area = 1/2*a*b*sin C
9 times 11 times the depth. You need 3 dimensions.
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2
If the 3 sides are x, y and z then let s = (x+y+z)/2 Area = sqrt[s*(s-x)*(s-y)*(s-z)] sq cm.
Use Pythagoras' theorum a2 = b2 + c2 a2 = (9x9) + (12x12) 225 = 81 + 144 Ö225 = 15cm > 14cm. answer NO.
By using the cosine rule in trigonometry the biggest angle works out as 106.23 degrees.
Area is length times width. So... 9x9=81