It is simply 10 to that power.
Thus, antilog(231) = 10231. Could not be simpler.
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No.
Yes, unless the 3 digit number is negative, or a decimal.
Largest 4 digit number = 9999 Smallest 3 digit number = 111 9999 - 111 = 9888 Largest 4 digit number = 9999 Smallest 3 digit number = 111 9999 - 111 = 9888
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
By using the 3 digits of a number we can form 3 different two digit numbers. 3C2 = 3!/[(3 - 2)!2!] = 3!/(1!2!) = (3 x 2!)/2! = 3