To determine if 12m, 4m, and 2m can form a right triangle, we apply the Pythagorean theorem, which states that for a right triangle, the square of the length of the longest side (hypotenuse) must equal the sum of the squares of the other two sides. Here, the longest side is 12m. Calculating, (12^2 = 144) and (4^2 + 2^2 = 16 + 4 = 20). Since 144 does not equal 20, these lengths cannot form a right triangle.
To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.
12m + 9n - 4 - 10m + 6n = 2m + 15n - 4
The expression (-a 6m - 3a 2m) can be simplified by factoring out the common terms. It can be rewritten as (-a(6m + 3 \cdot 2m)). Simplifying further, it becomes (-a(6m + 6m) = -a(12m)) or (-12am).
A triangle with side lengths of 12 m, 4 m, and 2 m cannot exist because it violates the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4 m + 2 m is not greater than 12 m, so these side lengths cannot form a triangle.
Height is 2m
10m - 7
To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.
12m + 9n - 4 - 10m + 6n = 2m + 15n - 4
The expression (-a 6m - 3a 2m) can be simplified by factoring out the common terms. It can be rewritten as (-a(6m + 3 \cdot 2m)). Simplifying further, it becomes (-a(6m + 6m) = -a(12m)) or (-12am).
12m X 2m x 5cm
A triangle with side lengths of 12 m, 4 m, and 2 m cannot exist because it violates the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4 m + 2 m is not greater than 12 m, so these side lengths cannot form a triangle.
A triangle doesn't have volume.
yas
Height is 2m
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
m2 + 8m - 65 = (m + 13) (m - 5)
Please be more specific with your question. If you mean 2cm, then the area will be 12cm squared. If you mean 2m then the area will be 12m squared.