To determine if 12m, 4m, and 2m can form a right triangle, we apply the Pythagorean theorem, which states that for a right triangle, the square of the length of the longest side (hypotenuse) must equal the sum of the squares of the other two sides. Here, the longest side is 12m. Calculating, (12^2 = 144) and (4^2 + 2^2 = 16 + 4 = 20). Since 144 does not equal 20, these lengths cannot form a right triangle.
4m
first, multiply the base and height then divide it into 2 example: base:4m height:2m multiply 4 by 2= 8 then divide 8 by 2= 4 4m squared
6m + 5n - 4m + 7n = 2m + 12n
A 4 square meter area is a space that measures 4 square meters in total. For example, if it were a square, each side would measure approximately 2 meters (since 2m x 2m = 4m²). This size is equivalent to a small room or a large bathroom, providing enough space for various uses.
To determine if 12m, 4m, and 2m can form a right triangle, we apply the Pythagorean theorem, which states that for a right triangle, the square of the length of the longest side (hypotenuse) must equal the sum of the squares of the other two sides. Here, the longest side is 12m. Calculating, (12^2 = 144) and (4^2 + 2^2 = 16 + 4 = 20). Since 144 does not equal 20, these lengths cannot form a right triangle.
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
It is: 2m times 2m is equivalent to 4m^2
Well, darling, if the length of your rectangle is 4m and the width is 2m, then the perimeter is simply calculated by adding up all the sides, which gives you 4m + 4m + 2m + 2m, totaling 12 meters. Voilà, there's your answer!
m2 + 8m - 65 = (m + 13) (m - 5)
4m
6m + 7 - 2m + 1 = 4m + 8 If you meant: (6m + 7) - (2m + 1) = 4m + 6
40m^3
first, multiply the base and height then divide it into 2 example: base:4m height:2m multiply 4 by 2= 8 then divide 8 by 2= 4 4m squared
It appears to be a scalene triangle from the given dimensions.
The two monomials with a greatest common factor of 4M would be 4M and another monomial that includes 4M as a factor. For example, 4M and 12M would have a greatest common factor of 4M. This is because both 4M and 12M can be divided by 4M without a remainder. The greatest common factor represents the largest monomial that can divide evenly into both monomials.
40 cubic meters