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Can 12m 4m and 2m make a right triangle?
To determine if 12m, 4m, and 2m can form a right triangle, we apply the Pythagorean theorem, which states that for a right triangle, the square of the length of the longest side (hypotenuse) must equal the sum of the squares of the other two sides. Here, the longest side is 12m. Calculating, (12^2 = 144) and (4^2 + 2^2 = 16 + 4 = 20). Since 144 does not equal 20, these lengths cannot form a right triangle.
Can 8m 4m and 2m make a right triangle?
To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.
What is 2m x 2m in square centimetres?
4m
What is the area for triangle?
first, multiply the base and height then divide it into 2 example: base:4m height:2m multiply 4 by 2= 8 then divide 8 by 2= 4 4m squared
6m plus 5n-4m plus 7n equals?
6m + 5n - 4m + 7n = 2m + 12n
Can 12m 4m and 2m make a right triangle?
To determine if 12m, 4m, and 2m can form a right triangle, we apply the Pythagorean theorem, which states that for a right triangle, the square of the length of the longest side (hypotenuse) must equal the sum of the squares of the other two sides. Here, the longest side is 12m. Calculating, (12^2 = 144) and (4^2 + 2^2 = 16 + 4 = 20). Since 144 does not equal 20, these lengths cannot form a right triangle.
What triangle measures 2m 4m and 7m?
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
What is 2m x 2m?
It is: 2m times 2m is equivalent to 4m^2
If length of a rectangle is 4m and width is 2m what is the perimeter?
Well, darling, if the length of your rectangle is 4m and the width is 2m, then the perimeter is simply calculated by adding up all the sides, which gives you 4m + 4m + 2m + 2m, totaling 12 meters. Voilà, there's your answer!
How do you factor 12m plus 16m squared plus 8m cubed?
m2 + 8m - 65 = (m + 13) (m - 5)
Can 8m 4m and 2m make a right triangle?
To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.
What is 2m x 2m in square centimetres?
4m
6m plus 7 - 2m plus 1?
6m + 7 - 2m + 1 = 4m + 8 If you meant: (6m + 7) - (2m + 1) = 4m + 6
A box is 5m by 4m by 2m what is the volume?
40m^3
What is the area for triangle?
first, multiply the base and height then divide it into 2 example: base:4m height:2m multiply 4 by 2= 8 then divide 8 by 2= 4 4m squared
What type of traingle measures 4m 10m 8m?
It appears to be a scalene triangle from the given dimensions.
What two monomials whose greatest common factor is 4M?
The two monomials with a greatest common factor of 4M would be 4M and another monomial that includes 4M as a factor. For example, 4M and 12M would have a greatest common factor of 4M. This is because both 4M and 12M can be divided by 4M without a remainder. The greatest common factor represents the largest monomial that can divide evenly into both monomials.
