yea if it isn't AxAxA or a+a+a
Chat with our AI personalities
If I understand your question correctly, such a sequence is an = x cos(πx). It has neither an upper nor lower bound. It's divergent, but its limit is neither infinity nor negative infinity.
Neither true nor false. Some theorems can be proven using geometric arguments and methods, others cannot.
No. Although the ratios of the terms in the Fibonacci sequence do approach a constant, phi, in order for the Fibonacci sequence to be a geometric sequence the ratio of ALL of the terms has to be a constant, not just approaching one. A simple counterexample to show that this is not true is to notice that 1/1 is not equal to 2/1, nor is 3/2, 5/3, 8/5...
Neither, then nor; eg neither Jack nor John can ski.
We use neither nor when we have to say two things that have not happened. Like neither me nor my friend was allowed to take the ride.