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What is the greatest number of intersection points possible with just 4 lines?
The greatest number of intersection points with just four lines is 6.
What is the greatest number of intersection points that four co planar lines can have?
The greatest number is six.
How many common points for intersection of four lines?
- If you're working on a single sheet of paper (2-D), then you can draw four lines that intersect in 1, 2, 3, 4, 5, or 6 points. - If in 3-D space, then you can also draw four lines that don't intersect at all.
Can four lines have seven intersection points?
No. In plane geometry, two lines can intersect at at most one point. This means that for n points, the maximum number of intersections is limited by the number of pairs of lines. For lines a,b,c,d, there are six pairs: (a,b), (a,c), (a,d), (b,c), (b,d), (c,d). So four lines can have at most six intersections.
How many straight lines can be formed by connecting any 2 of the 6 non-collinear points?
15 Consider one of the points. Call it point A. You can draw one line containing A through each of the other five lines (i.e., there are five lines that contain both A and another of the five points). Now, consider another of the points -- call it B. Excluiding the line that contains A and B, there are four lines that can be drawn containing B and one of the other four points. Continue this process for all the points. You get 5+4+3+2+1=15 lines. In general, if you have n non-collinear points, there are n+(n-1)+(n-2)+...+2+1=n*(n+1)/2 lines that can be drawn through any two of those points.
What is the greatest number of intersection points possible with just 4 lines?
The greatest number of intersection points with just four lines is 6.
Lines m and n are parallel if lines m and n are cut by three different transversals which also what is the least number of points of intersection that can occur among five lines?
four
What is the greatest number of intersection points that four co planar lines can have?
The greatest number is six.
Can four lines have only two intersection points?
No, four lines can can have 6 total intersections. They would be Ab, Ac, Ad, Bc, Bd, and Cd
What is the maximum number of points of intersection when three distinct circles and four distinct lines?
discuss the possible number of points of interscetion of two distinct circle
How many common points for intersection of four lines?
- If you're working on a single sheet of paper (2-D), then you can draw four lines that intersect in 1, 2, 3, 4, 5, or 6 points. - If in 3-D space, then you can also draw four lines that don't intersect at all.
How do you play blox on smallworlds?
you have to make four or five horizontal lines in order to get 100 points.
Can you arrange the numbers 1-10 on the points of intersection so that the four numbers on each line total 22?
On a five point star
What is the greatest number of intersection points four coplanar lines can have?
6! Thank you to ChaCha Answers. Wiki sucks, compared to ChaCha. :) -Geometry Student from TX
Can four lines have seven intersection points?
No. In plane geometry, two lines can intersect at at most one point. This means that for n points, the maximum number of intersections is limited by the number of pairs of lines. For lines a,b,c,d, there are six pairs: (a,b), (a,c), (a,d), (b,c), (b,d), (c,d). So four lines can have at most six intersections.
How can four lines have six intersection points?
you cross two lines like a tepee, then run a line through the bottom of the tepee, then make a line go slanted through the bottom line then one tepee side, then the other
How many straight lines can be formed by connecting any 2 of the 6 non-collinear points?
15 Consider one of the points. Call it point A. You can draw one line containing A through each of the other five lines (i.e., there are five lines that contain both A and another of the five points). Now, consider another of the points -- call it B. Excluiding the line that contains A and B, there are four lines that can be drawn containing B and one of the other four points. Continue this process for all the points. You get 5+4+3+2+1=15 lines. In general, if you have n non-collinear points, there are n+(n-1)+(n-2)+...+2+1=n*(n+1)/2 lines that can be drawn through any two of those points.
