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What is average of first 100 even numbers?
The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.
How do you compare addition and multiplication?
Although the sum of two numbers equals their product for only one certain value (apart from 0 of course), multiplication may be considered as a short-cut way to perform a string of additions. I'll leave you to deduce that singular value N for which N + N = N X N.
How do you find the mean of first n natural numbers?
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
What are the trainglar numbers?
I have no idea about trainglar numbers. Triangular numbers are numbers of the form n*(n+1)/2 where n is an integer.
What is true about the sum of 2 odd numbers?
Sum of two odd numbers is always an even number.e.g. 1 + 7 = 8Explanation:The successor of an odd number is an even number and the successor is obtained by adding 1.Let us assume any odd number, say n.On adding 1(i.e. an odd number) to n we get an even number and again on addition of 1 or addition of 2(an even number) to n we get an odd number. If we continue to add like this we get to know that addition of two odd numbers is always an even number.
What is the sum of the first n numbers?
Assuming you mean the first n counting numbers then: let S{n} be the sum; then: S{n} = 1 + 2 + ... + (n-1) + n As addition is commutative, the sum can be reversed to give: S{n} = n + (n-1) + ... + 2 + 1 Now add the two versions together (term by term), giving: S{n} + S{n} = (1 + n) + (2 + (n-1)) + ... + ((n-1) + 2) + (n + 1) → 2S{n} = (n+1) + (n+1) + ... + (n+1) + (n+1) As there were originally n terms, this is (n+1) added n times, giving: 2S{n} = n(n+1) → S{n} = ½n(n+1) The sum of the first n counting numbers is ½n(n+1).
What numbers is 1 a factor of?
All numbers. n x 1 = n It doesn't matter what n is.
What is average of first 100 even numbers?
The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.
How do you compare addition and multiplication?
Although the sum of two numbers equals their product for only one certain value (apart from 0 of course), multiplication may be considered as a short-cut way to perform a string of additions. I'll leave you to deduce that singular value N for which N + N = N X N.
How do you find the mean of first n natural numbers?
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
The variance of first n natural numbers is?
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
What are the trainglar numbers?
I have no idea about trainglar numbers. Triangular numbers are numbers of the form n*(n+1)/2 where n is an integer.
The average of three consecutive numbers?
For any set of numbers n-1, n, and n+1, the average will be n. For example, if the numbers are 18, 19, 20, the average will be 19.
What is true about the sum of 2 odd numbers?
Sum of two odd numbers is always an even number.e.g. 1 + 7 = 8Explanation:The successor of an odd number is an even number and the successor is obtained by adding 1.Let us assume any odd number, say n.On adding 1(i.e. an odd number) to n we get an even number and again on addition of 1 or addition of 2(an even number) to n we get an odd number. If we continue to add like this we get to know that addition of two odd numbers is always an even number.
What are three consecutive numbers that sum to 771?
256, 257, 258 Let the three numbers be n-1, n, n+1, then: (n-1) + n + (n+1) = 771 → 3n = 771 → n = 257 → the three numbers are 257-1 = 256, 257 and 257+1 = 258
What are the 3 numbers of the three consecutive?
n-1, n and n+1 where n is an integer.
Write a program to read a positive integer N and find the average of all even numbers between 1 and N inclusive Perform any necessary validates?
int AverageEvenNumbers( int n ) { return ( n / 2 ) + 1; } n / 2 will always give you an int, aka no decimals if n is 5 the even numbers are 2 and 4, the average is 3 (5) / 2 is 2 2 + 1 is 3 if n is 10 the even numbers are 2 4 6 8 10, the average is 6 10 / 2 is 5 5 + 1 is 6 enjoy
