Carefully arrange 12 rows with 8 coins in each row.
Two ways only. 4 rows with 25 stamps each or 5 rows with 20 stamps each.
90000
To do that, we'll need the factor pairs of 120. (120, 1) (60, 2) (40, 3) (30, 4) (24, 5) (20, 6) (15, 8) (12, 10) Choose the pairs that have an odd and even number. Looks like 4 of them.
wait not the discription srry
You can't arrange 12 apples into 5 rows with four in each. To do that you would need 20 apples because 5 rows of 4 = 20 or 5x4=20. You can arrange 12 apples into 3 groups of 4 because 3x4=12
4
Carefully arrange 12 rows with 8 coins in each row.
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.
There are eight possible combinations... 1 row of 24 cans 2 rows of 12 cans 3 rows 8 cans 4 rows of 6 cans 6 rows of 4 cans 8 rows of 3 cans 12 rows of 2 cans 24 rows of 1 can
Two ways only. 4 rows with 25 stamps each or 5 rows with 20 stamps each.
in the form of a start
oooo arrange them in a triangle shape, four coins each side. o o oo o
Oh, dude, arranging 6 counters in equal rows is like a puzzle, man. So, if you're into math and stuff, there are 720 different ways you can do it. But hey, who's counting, right? Just go with the flow and arrange those counters however you like.
2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.
by 2 rows
1 row of 100 chairs. 2 rows of 50 chairs. 4 rows of 25 chairs. 5 rows of 20 chairs. 10 rows of 10 chairs. 20 rows of 5 chairs. 25 rows of 4 chairs. 50 rows of 2 chairs. 100 rows of 1 chair. Or you could put them all in one big circle.