Yes, each would have 14, as 14 x 4 = 56.
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Carefully arrange 12 rows with 8 coins in each row.
Two ways only. 4 rows with 25 stamps each or 5 rows with 20 stamps each.
90000
To do that, we'll need the factor pairs of 120. (120, 1) (60, 2) (40, 3) (30, 4) (24, 5) (20, 6) (15, 8) (12, 10) Choose the pairs that have an odd and even number. Looks like 4 of them.
wait not the discription srry