Tags Algebra Calculus Trigonometry

Animals & Plants Arts & Entertainment Auto Beauty & Health Books and Literature Business Electronics Engineering & Technology Food & Drink History Hobbies Jobs & Education Law & Government Math People & Society Science Social Studies Sports Travel & Places

0

Subjects>Math>Math & Arithmetic

Can you integrate -cos x plus c?

Anonymous

∙ 12y ago

Updated: 12/21/2022

Why not? Just a second integration. Drop the constant.

int[- cos(x)] dx

the negative implies - 1 and can be brought out side the integrand

- int[cos(x)] dx

= - sin(x) + C

==========

Wiki User

∙ 12y ago

Still curious? Ask our experts.

Chat with our AI personalities

Steve

Knowledge is a journey, you know? We'll get there.

Chat with Steve

Taiga

Every great hero faces trials, and you—yes, YOU—are no exception!

Chat with Taiga

Vivi

Your ride-or-die bestie who's seen you through every high and low.

Chat with Vivi

Add your answer:

Earn +20 pts

Q: Can you integrate -cos x plus c?

Write your answer...

Submit

Still have questions?

imp

Continue Learning about Math & Arithmetic

How do you integrate sinx divide sinx plus cosx?

1/2(x-ln(sin(x)+cos(x)))

Cos x equals -cos x plus 1?

No, but cos(-x) = cos(x), because the cosine function is an even function.

How do you prove that (1 plus cotx)2-2cotx 1(1-cos)(1 plus cos)?

Manipulate normally, noting:cot x = cos x / sin xcos² x + sin² x = 1 → sin²x = 1 - cos² xa² - b² = (a + b)(a - b)1 = 1²ab = baa/(bc) = a/b/c(1 + cot x)² - 2 cot x = 1² + 2 cot x + cot² x - 2 cot x= 1 + cot² x= 1 + (cos x / sin x)²= 1 + cos² x / sin² x= 1 + cos² x / (1 - cos² x)= ((1 - cos² x) + cos² x)/(1 - cos² x)= 1/(1² - cos² x)= 1/((1 + cos x)(1 - cos x))= 1/(1 - cos x)/(1 + cos x)QED.

How do you express sin x plus cos x divided by cos x in terms of tan x?

(sin x + cos x) / cosx = sin x / cos x + cosx / cos x = tan x + 1

How do you solve sinx divided by 1 plus cosx plus cosx divided by sinx?

sin x/(1+cos x) + cos x / sin x Multiply by sin x (1+cos x) =[(sin^2 x + cos x(1+cos x) ] / sin x (1+cos x) = [(sin^2 x + cos x + cos^2 x) ] / sin x (1+cos x) sin^2 x + cos^2 x = 1 = (1+cos x) / sin x (1+cos x) = 1/sin x

Trending Questions

How is a square different for a cude? What is 35 over 49 in the simplest form? Why is two thirds and six eighths NOT equivalent? What unit is smaller than a mile? What is 2 to the power of 2 over 3? What is the ratio of 6 and 15? How are Aristotle's teaching related to the scientific method used by scientists today? What can go into 10 and 3? How many 17 go into 51? What year should a person be born to be 70 years old? How do you write extended form of 804500? How many numbers between 1 and 100 (inclusive) are divisible by 3 or 4? What is mean proportion? What is the positive factors of 25? How do you find the acres? How do you write 82.67 million in numbers? What unit is described as '? How many degrees of each interior angle measure of a regular octagon? What is Recurring deposit account? What is 4 h 21 mins plus 7 h 52 min?

Related Questions

How do you integrate 2sinxcosx?

Integrate 2sin(x)cos(x)dxLet u = cos(x) and du = -sin(x)dx and pull out the -2:-2[Integral(u*du)]Integrate with respect to u:-2(u2)/2 + CSimplify:-u2 + CReplace u with cos(x):-cos2(x) + C

How do you integrate sinx divide sinx plus cosx?

1/2(x-ln(sin(x)+cos(x)))

What is the antiderivative of -cscxcotx?

First, antiderivative = a solution to the indefinite integral therefore to integrate -(csc(x))(cot(x)) first convert it to -cos(x)/sin2(x) To integrate ∫-cos(x)/sin2(x) dx, use substitution u = sin(x) and du/dx = cosx This will make it ∫-1/u2 du and the antiderivative is 1/u +c, therefore the answer is 1/sin(x) + c.

Integration of tangent x?

To integrate tan(x), you must break up tangent into sine over cosine, with that being done, all you have is a u-substitution with the cosine. This should give: int(tan(x)dx)=int(sin(x)/cos(x)dx)=int(-(1/u)*du)=-ln|u|+C=-ln|cos(x)|+C u=cos(x) du=-sin(x)dx

Cos x equals -cos x plus 1?

No, but cos(-x) = cos(x), because the cosine function is an even function.

Integrate sin x cos 2x?

By Angle-Addition, cos(2x) = 2cos(x)^2-1 So, sin(x)cos(2x) = [2cos(x)^2-1]sin(x) = 2sin(x)cos(x)^2 - sin(x) Int[2sin(x)cos(x)^2 - sin(x)] = (-2/3)cos(x)^3 + cos(x) +K

How do you prove that (1 plus cotx)2-2cotx 1(1-cos)(1 plus cos)?

Manipulate normally, noting:cot x = cos x / sin xcos² x + sin² x = 1 → sin²x = 1 - cos² xa² - b² = (a + b)(a - b)1 = 1²ab = baa/(bc) = a/b/c(1 + cot x)² - 2 cot x = 1² + 2 cot x + cot² x - 2 cot x= 1 + cot² x= 1 + (cos x / sin x)²= 1 + cos² x / sin² x= 1 + cos² x / (1 - cos² x)= ((1 - cos² x) + cos² x)/(1 - cos² x)= 1/(1² - cos² x)= 1/((1 + cos x)(1 - cos x))= 1/(1 - cos x)/(1 + cos x)QED.

What is the integration of tanx?

The integral of tan(x) dx = ln | sec(x) | + cto solve... tan(x) = sin(x)/cos(x)the integral of (sin(x)/cos(x) dx) ... let u = cos(x) then du = -sin(x) dx= the integral of (1/u -du)= -ln | u | + c= -ln | cos(x) | + c= ln | (cos(x))^-1 | + c ... or ... ln | 1/cos(x) | + c= ln | sec(x) | + c

How do you express sin x plus cos x divided by cos x in terms of tan x?

(sin x + cos x) / cosx = sin x / cos x + cosx / cos x = tan x + 1

How do you solve sinx divided by 1 plus cosx plus cosx divided by sinx?

sin x/(1+cos x) + cos x / sin x Multiply by sin x (1+cos x) =[(sin^2 x + cos x(1+cos x) ] / sin x (1+cos x) = [(sin^2 x + cos x + cos^2 x) ] / sin x (1+cos x) sin^2 x + cos^2 x = 1 = (1+cos x) / sin x (1+cos x) = 1/sin x

What is the integral of zero to pai by two x cos cubed x?

(3pi-7)/9 To verify this go to the link and enter integrate x cos(x)^3 from 0 to pi/2.

Sin x plus cos x?

sin(x) + cos(x) = sqrt(2) · sin(45°+x)

Resources

Top Categories

Product

Company

Copyright ©2025 Infospace Holdings LLC, A System1 Company. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Answers.