The prime factors of 56 are: 2, 7
The factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 42. The factors of 56 are 1, 2, 4, 7, 8, 14, 28, and 56.
2 and 7
As a product of its prime factors: 2*2*2*7 = 56
There are 56 of them and I am not inclined to list them all.
The factors of 28 are: 1 2 4 7 14 28 & The factors of 56 are: 1 2 4 7 8 14 28 56 Answer: 1 2 4 7 14 28
The factors of 56 are 1, 2, 4, 7, 8, 14, 28 and 56. 2 and 7 are prime. To be common, they need to be compared to another list of factors.
1,2,4,7,8,14,28,and 56 are the factors of 56 1,2,3,4,6,7,12,14,21,28,42,and 84 are the factors of 84. wait did you mean 56 and 84 or the number 5684?
The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56.
The factors of 56 are 1, 2, 4, 7, 8, 14, 28 and 56.
The factors of 56: 1, 2, 4, 7, 8, 14, 28, 56.
The factors of 56 are 1, 2, 4, 7, 8, 14, 28, and 56.
The factors of 40 are: 1 2 4 5 8 10 20 40 & The factors of 56 are: 1 2 4 7 8 14 28 56
Prime factors are: 25 x 7 Divisors are: 1, 2, 4, 7, 8, 14, 16, 28, 32, 56, 112, 224
1 and 7
The common factors are: 1, 2, 4, 8.
The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.