To graph a linear equation, you must determine what a and b are for the equation y=ax+b. For this example, a=-1 and b=4. A is the slope and b is the y-intercept. The slope is the height of the line over the length of it. In this equation, the line goes down one unit for each unit right. The y-intercept refers to where the line crosses the y axis. For this example, it crosses the y axis at y=4. The line will cross the y axis at y=4 and then goes down and to the right and up and to the left. It will cross the x axis at x=4.
the graph is moved down 6 units
The graph of that equation is a circle, centered at the origin, with radius = 2 .
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
the graph is moved down 6 units
y=-10x-4
Upwards.
(0,4) and (-2, 0)
The graph of that equation is a circle, centered at the origin, with radius = 2 .
That's not an equation, so there's nothing to graph. Simple way to tell: There's no "equals" sign in it.
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
First convert it to Y= y-x+4=0 y=x-4 The graph has a slope of 1 and the y-intercept is (0,-4)
-9
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
y = 2x+3 + 4 cuts the y axis when x = 0 so y = 23 + 4 = 8 + 4 = 12. Therefore, the point is (0, 12).