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How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
What is 100000 log?
100000 log = 5.
What will be the log reduction value if the number reduces from 5 to 0 or 5 to 1?
log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990
What is 5 to the 200 power?
5²⁰⁰ = 62,230,152,778,611,417,071,440,640,537,801,242,405,902,521,687,211,671,331,011,166,147,896,988, 340,353,834,411,839,448,231,257,136,169,569,665,895,551,224,821,247,160,434,722,900,390,625
How do you isolate x in this equation 1 equals leftbracket 1 plus x right bracket exponent 5?
with something called logarithms. So 1 = (1 + x)^5 log 1 = log ((1+x)^5) log 1 = 5 x log (1 +x) but log 1 = 0 therefore 0 = 5 x log(1+x) divide both sides by 5 and you get 0 = log (1+x) we know that log 1 = 0, therefore 1+ x = 1 and so x = 0
What is the value of log5 plus log 5 10 - log 5 4?
1.268293446
What is the value of log 5 19 rounded to the nearest hundredth?
5.00
Is log 5 equivalent to log 5-log 20?
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
When you calculate log5 you would be finding the value of what expression?
The base of log, if unspecified, is taken to be 10 so you would be finding the value of the logarithm of 5 to the base 10.This is the value x, such that 10^x = 5.
How do i calculate Biologic log reduction?
Microbial load (cfu/g or cfu/ml) can be expressed as log10. So, if you have 100,000 microbes that is 5 log, 10,000 microbes is 4 log, 1,000 is 3 log, 100 microbes is 2 log and 10 microbes is 1 log. Now, if you went from 100,000 microbes cfu/g to 10,000 microbes cfu/g that would be a 1 log reduction (5 - 4 log). If you went from 100,000 to 32,000 that would be a 0.5 log reduction (5 - 4.5 log) and so on. I hope this helps St John Hall
How would you rewrite 7 to the power of x equals 5?
7x = 5x log(7) = log(5)x = log(5) / (log(7) = 0.82709 (rounded)
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
What is 100000 log?
100000 log = 5.
Log 5 plus log 2 equals?
log (6x + 5) = 26x + 5 > 06x + 5 - 5 > 0 - 56x > - 56x/6 > -5/6x > -5/6log (6x + 5) = 210^2 = 6x + 5100 = 6x + 5100 - 5 = 6x + 5 - 595 = 6x95/6 = 6x/695/6 = xCheck:
What will be the log reduction value if the number reduces from 5 to 0 or 5 to 1?
log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990log(0) is not defined, so the first part of the question cannot be answered.log(5) = 0.6990 and log(1) = 0 so the reduction is 0.6990
What is 5 to the 200 power?
5²⁰⁰ = 62,230,152,778,611,417,071,440,640,537,801,242,405,902,521,687,211,671,331,011,166,147,896,988, 340,353,834,411,839,448,231,257,136,169,569,665,895,551,224,821,247,160,434,722,900,390,625
What is 6255 to the power 2 5 to the power of?
6225^2=5^x 38,750,625=5^x log(38,750,625)=xlog(5) log(38,750,625)/log(5)=x x is approximately 10.856
