i believe it is 7lnx, but don't quote me on it.
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NO! Lnx + Ln2= 2 + Lnx implies Ln2 = 2 which implies 2 = e2 which is simply not true.
lnx + lnx +3 = (ln55)/4 2lnx +3 =(ln55)/4 8lnx + 12=ln55 8lnx=-12+ln55 lnx=(-12+ln55)/8 x=e^[(-12+ln55)/8]
lnx + .5lny - 5lnz First, make the coefficients into exponents: lnx + ln(y^.5) - ln(z^5) ln[xy^.5] - ln(z^5) ln[(xy^.5)/z^5] There you go!
If: u = 1+lnx Then: x = (u-1)/(ln)
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