73,991 cubic units.
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Each half-sphere occupies a height of 4. Effectively, there is a full sphere of radius 4 and a cylinder of length 4. The volume of the sphere = 4/3πr³ = 4/3π4³ = 268.08 The volume of the cylinder = πr²h = π4² x 4 = 201.06 Total volume = 268.08 + 201.06 = 469.14 (2dp)
The volume of the cylinder is height * pi * radius squared. Fill up the cylinder with water. Pour it into the irregular. If it's not full yet, do it again as many times until it is. Count how many times you filled & poured the entire cylinder full of water. Multiply that number by the volume of the cylinder. (First part of answer) If you can only fit a portion of the last cylinder full of water into the irregular, measure how much water you have left in the cylinder. Multiply (1-portion left (a fraction less than 1)) times the volume of the cylinder to get the volume of the last bit used to fill up the irregular. (second part of answer) Add the two parts of the answer to get the final answer.
Calculate the volume of full cone. For this you need to reproduce the cone surface upto the point where radius becomes zero.Then deduct the volume of the portion which is cut from the full volume. You can't multiply the height to the average of bottom area and top area. Because area (pi.r^2) is the second degree function of radius, not first degree.
Volume of a cylinder = (pi) (radius)2 (height)Radius = 6.5-ftHeight = 3-ft 6-in = 3.5-ftVolume = (pi) (6.5)2 (3.5) = 464.56 cubic feet = 3,475 gallons full to the brim.
The pool is a cylinder. Volume of a cylinder = (pi) x (radius)2 x (height or depth).Volume = (pi) x (12')2 x (3') = 432 pi cubic feet = 1357.17 ft3 = 10,152.3 gallons (rounded)That's the volume of the pool. I have no way of knowing how much water is in it.It could be empty, half empty, full of mud and old leaves, etc.