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What is the period of y equals tan2x?
The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2
How would you solve the integral of 1 plus tan2x plus tan squared 2x?
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
What is the period and amplitude for y equals 7 cos 2x?
amplitude =7. to find the period, set 2x equal to 2∏. then x=∏=period
Is there a graph of y equals equals 2 tan 2x?
Yes, that is a shifted tanX graph, just as you would shift any graft.
Determine the x coordinate of the point where the derivative of y equals x square - 2x equals 0?
x=2
What is the period of y equals tan2x?
The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2
What is the answer to y equals 2 tan 2x?
y = 2*tan(2x) is an equation in two variable. There can be no answer. While x can be made the subject of the formula, that is not an *answer*.
How do you prove tan x plus tan x sec 2x equals tan 2x?
tan x + (tan x)(sec 2x) = tan 2x work dependently on the left sidetan x + (tan x)(sec 2x); factor out tan x= tan x(1 + sec 2x); sec 2x = 1/cos 2x= tan x(1 + 1/cos 2x); LCD = cos 2x= tan x[cos 2x + 1)/cos 2x]; tan x = sin x/cos x and cos 2x = 1 - 2 sin2 x= (sin x/cos x)[(1 - 2sin2 x + 1)/cos 2x]= (sin x/cos x)[2(1 - sin2 x)/cos 2x]; 1 - sin2 x = cos2 x= (sin x/cos x)[2cos2 x)/cos 2x]; simplify cos x= (2sin x cos x)/cos 2x; 2 sinx cos x = sin 2x= sin 2x/cos 2x= tan 2x
Y equals 2x-2x-24 determine the roots of the function?
If Y equals 2X - 2X - 24, then there is one root, and it is -24. The two 2X's cancel each other out.
How would you solve the integral of 1 plus tan2x plus tan squared 2x?
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
What is the period and amplitude for y equals 7 cos 2x?
amplitude =7. to find the period, set 2x equal to 2∏. then x=∏=period
Is there a graph of y equals equals 2 tan 2x?
Yes, that is a shifted tanX graph, just as you would shift any graft.
What is the period of the equation y equals -6 sin 2x?
Pi
Which functions have a period of Pi?
sin(2x), cos(2x), cosec(2x), sec(2x), tan(x) and cot(x) are all possible functions.
What is the period of y equals sin 2x?
Pi radians (180 degrees) is.
Determine the x coordinate of the point where the derivative of y equals x square - 2x equals 0?
x=2
What is the derivative of secant 2X?
d/dx sec(2x) = 2sec(2x)tan(2x)
