(x2-x-12)/(x-4) = (x+3)
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x2 - x - 12First try and factor that expression.Notice that it happens to be the product of (x - 4) and (x + 3). This makes your problem easy.(x2 - x - 12) / (x - 4)= (x - 4) (x + 3) / (x - 4)Now just divide numerator and denominator by the common factor. ("Cancel" (x - 4) out of numerator and denominator.)Wind up with the answer = (x + 3)
14
x2-7x+12 (x-3)(x-4)
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
(x2 - 4)/4x = 12; x ≠ 0 x2 - 4 = 48x x2 - 48x = 4 x2 - 48x + 242= 4 + 242 (x - 24)2 = 4 + 576 x - 24 = ±√580 x = 24 ± 2√145