x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2
x2 - 10x - 24= x2 - 12x + 2x - 24= x(x - 12) + 2(x - 12)= (x - 12)(x + 2)
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
x = 0
x2 - 7x = 60 x2 - 7x - 60 = 0 (x - 12) (x + 5) = 0 x = 12 or x = -5
x2 - 18x + 72 = 0 (x - 6)(x - 12) = 0 x ∈ {6, 12}
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
Im assuming you mean x2 (x squared). This equation will be a quadratic. so... x2+144=-24x subtract -24x from itself and the other side -24x -24x ----------------- x2-24x+144=0 now break it down even further (x-12)(x-12)=0 Now you solve the "mini-equations" x-12=0 x-12=0 +12 +12 +12 +12 --------------------------- x=12 or x=12 hope it helps!!!
x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
(x + 12)(x - 6) = 0 x = 6 or -12
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
x²-x-12=0 x1=-(-1/2) - Square root of ((-1/2)²+12) x1=0.5 - 3.5 x1=-3 x2=-(-1/2) + Square root of ((-1/2)²+12) x2=0.5 + 3.5 x2=4
2x2 = 10x + 12 2x2 - 10x - 12 = 0 x2 -5x -6 = 0 x2 - 6x + x - 6 = 0 x(x -6) + 1(x -6) = 0 (x+1)(x-6) = 0 x = -1 or x = 6
x2 - x -12 = 0 x2 - 4x + 3x -12 = 0 x(x - 4) + 3(x - 4) = 0 (x + 3)(x - 4) = 0 (x + 3) = 0 or (x - 4) = 0 So x = -3 or x = 4