x2 - x - 12 = 0
∴ (x + 3)(x - 4) = 0
∴ x ∈ {-3, 4}
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x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2
x2 - 10x - 24= x2 - 12x + 2x - 24= x(x - 12) + 2(x - 12)= (x - 12)(x + 2)
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}