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What is the square of n squared plus 2n minus 1?
(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156
What is 2n squared plus 5n plus 2?
That factors to (2n + 1)(n + 2)
What is the answer for 7n plus 6n-5 equals 4n plus 4?
n = 1 7n + 6n - 5 = 4n + 4 13n - 5 = 4n + 4 13n - 4n - 5 = 4n - 4n + 4 9n - 5 = 4 9n -5 + 5 = 4 + 5 9n = 9 n = 1
6 equals 1 - 2n plus 5?
6=(1-2n)+5 6-5=(1-2n)+5-5 1=1-2n 1-1=1-1-2n 0=-2n 0/-2=-2n/-2 0=n
Twice the greater of two consecutive odd integers is 13 less than three times the lesser Find the integers?
The representation of an odd integer is 2n + 1. So the other consecutive odd integer will be 2n + 3,[(2n + 1) + 2]. Thus, we have:2(2n + 3) + 13 = 3(2n + 1)4n + 6 + 13 = 6n + 3 subtract 4n and 3 to both sides16 = 2n divide by 2 to both sides8 = n2n + 1 = 2(8) + 1 = 16 + 1 = 172n + 3 = 2(8) + 3 = 16 + 3 = 19Therefore, theses numbers are 17 an 19.Check:3(17) - 2(19) = 13 ?51 - 38 = 13?13 = 13 True
