(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156
n = 1 7n + 6n - 5 = 4n + 4 13n - 5 = 4n + 4 13n - 4n - 5 = 4n - 4n + 4 9n - 5 = 4 9n -5 + 5 = 4 + 5 9n = 9 n = 1
That factors to (2n + 1)(n + 2)
The representation of an odd integer is 2n + 1. So the other consecutive odd integer will be 2n + 3,[(2n + 1) + 2]. Thus, we have:2(2n + 3) + 13 = 3(2n + 1)4n + 6 + 13 = 6n + 3 subtract 4n and 3 to both sides16 = 2n divide by 2 to both sides8 = n2n + 1 = 2(8) + 1 = 16 + 1 = 172n + 3 = 2(8) + 3 = 16 + 3 = 19Therefore, theses numbers are 17 an 19.Check:3(17) - 2(19) = 13 ?51 - 38 = 13?13 = 13 True
6=(1-2n)+5 6-5=(1-2n)+5-5 1=1-2n 1-1=1-1-2n 0=-2n 0/-2=-2n/-2 0=n
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
If the given equation were factorized it would be: 2n2 + 4n = 2n(n+1) Another Answer:- The given expression when factored is 2n(n+2)
n(2n - 1)(2n + 7)
If you mean: 4n = 1-23-2n then 6n = -22 and so n = 11/3
7n -1n,0n,1n,2n,3n,4n,5n,6n,7n 1 2 3 4 5 6 7 8 9
If you mean: 4n = 1-23-2n then 6n = -22 and so n = 11/3
Any even number can be written in the form 2n for some natural number n.Any odd number can be written as 2n+1 for a natural number nNow add an even to an odd.2n+2n+1=4n+1 which is 2(2n)+1 and this is the form for an odd number.
The question can be represented as the equation, 2n + 5 = 4n + 3 where n is the unknown number. 2n + 5 = 4n + 3 : subtract 2n from both sides 5 = 2n + 3 : subtract 3 from both sides 2 = 2n : divide both sides by 2 1 = n The unknown number has been identified as 1.
FOIL deals with polynumerals in math. An example is a difference of squares as in (2n - 2)2 or (2n + 2)(2n - 2) =F stand for first--2n X 2n = 4n2O stands for outside-- 2n X -2 = -4nI stands for inside-- -2 X 2n = 4nL stands for last--2 X -2 = -4In the end you get:4n2 - 4n + 4n - 4 = 4n2 - 4Can you see how everything is squared and the two numbers are being subtracted?
It is an expression that can be simplified to -4n-1
4n+13=1 -13 -134n=-12/4 /4n=-3
(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156