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Nope. Consider x2+0x+1=0. This means x2+1=0. This has two solutions, but they are complex numbers: +i and -i, where i is the squareroot of -1.
How about x2+0x+0=0? This means x2=0. This has two solutions, sure, but they aren't distinct. In this case, x=0 for both solutions, so we just consider them one solution.
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How do you find the answer to a quadratic equation from the quadratic formula?
Plug 'a', 'b', and 'c' from the equation into the formula. When you do that, the formula becomes a pair of numbers ... one number when you pick the 'plus' sign, and another number when you pick the 'minus' sign. Those two numbers are the 'solutions' to the quadratic equation you started with.
What two numbers multiply to be 224 and add up to be a negative 84?
308
What is the discriminant of an algebra equation?
I am assuming that "an algebra equation" refers to a quadratic equation and not a higher polynomial.For a quadratic equation of the form y = ax^2 + bx + c, where a, b and c are real numbers and a is non-zero, the discriminant is b^2 – 4ac.
What is true of the disciminant when the two real numbers solutions to a quadratic equation are irrational numbers?
In that case, the discriminant is not a perfect square.
What two numbers multiply to negative 144 and add to positive 9?
153
Write a quadratic equation in the variable x having the given numbers as solution of 2?
x2 - 4x + 4 or (x - 2)2
Write a quadratic equation in the variable x having the given numbers as solutions Type the equation in standard form ax2 plus bx plus c equals 0 Solution 7 is the on solution?
0x2 + 1x - 7 = 0
How do you find the answer to a quadratic equation from the quadratic formula?
Plug 'a', 'b', and 'c' from the equation into the formula. When you do that, the formula becomes a pair of numbers ... one number when you pick the 'plus' sign, and another number when you pick the 'minus' sign. Those two numbers are the 'solutions' to the quadratic equation you started with.
What is the best way to estimate the solution of a quadratic equation?
I don't think there is any easy way to estimate it; just use the quadratic equation to calculate the solutions. You can round some of the numbers to get an estimate; in this case you might even do most of the calculation in your head, but it's probably easier just to do the full calculation.
What statement must be true of an equation before you can use the quadratic formula to find the solutions?
The quadratic formula can be used to find the solutions of a quadratic equation - not a linear or cubic, or non-polynomial equation. The quadratic formula will always provide the solutions to a quadratic equation - whether the solutions are rational, real or complex numbers.
What two numbers multiply to be 224 and add up to be a negative 84?
308
What is the discriminant of an algebra equation?
I am assuming that "an algebra equation" refers to a quadratic equation and not a higher polynomial.For a quadratic equation of the form y = ax^2 + bx + c, where a, b and c are real numbers and a is non-zero, the discriminant is b^2 – 4ac.
What is true of the disciminant when the two real numbers solutions to a quadratic equation are irrational numbers?
In that case, the discriminant is not a perfect square.
What two numbers multiply to negative 144 and add to positive 9?
153
Simplify 2t squared plus 8t plus 5 equals 0?
Let's simplify this together, friend. To solve the equation 2t^2 + 8t + 5 = 0, we can use the quadratic formula or factor it. If we factor, we look for two numbers that multiply to 2*5=10 and add up to 8. Once we find those numbers, we can rewrite the equation in factored form to find the solutions for t. Just take your time and enjoy the process of unraveling this mathematical mystery.
What is standrd form of quadratic equation?
Ax2 + Bx + C = 0A, B, and C are constants (numbers)
What are the compex roots in mathematics?
The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.
