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How do you find the height of a trapezoid if you have an area and both bases?
AREA = A = 1/2 (b1 + b2)(h) h= height = 2(A) / (b1 + b2)
What is the height of a trapezoid that has an area of 65 and bases that equal 13?
The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.
What is the formula for area of a trapazoid?
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
What is the formula for finding the area of the trapezoid?
The Trapezoid area formula would be (b1 + b2) H _________ 2 What this means is you add together both of the bases (top and bottom! and be sure to put b1 + b2 in parenthasis or you might loose points on a quiz!) then, the sum will be multiplied by the height. then once you have that, divide by 2.
What is the area of a trapezoid if the bases are 22 and 10 and the legs are 10?
Since the legs are both 10, it is an isosceles trapezium. Using Pythagoras's theorem, the height of the trapezium is 8 and so its area is 1/2*(22 + 10)*8 = 128 square units.
Does the area of the trapezoid double if one base doubles?
Answer: No.Explanation: Area of trapezoid = 1/2(b1 + b2) * h where b1 is length of base one, b2 is length of base 2 and h is height.this equation = 1/2*b1*h + 1/2*b2*hdouble one base:1/2(2*b1+b2) *h = b1*h+1/2*b2*h = (b1+1/2*b2)*hin order for the area to double, both bases would have to double which would cancel out both 1/2's. Only one is cancelled out so the area would increase but not double
How do you figure the height of a trapezoid?
1/2*(sum of both parallel bases)*height = area multiply both sides by 2 and then divide both sides by (sum of both parallel bases) height = (2*area) divided by (sum of both parallel sides)
How do you find the height of a trapezoid if you have an area and both bases?
AREA = A = 1/2 (b1 + b2)(h) h= height = 2(A) / (b1 + b2)
What is the height of a trapezoid that has an area of 65 and bases that equal 13?
The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.
What is the formula for area of a trapazoid?
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
How are a rectangle and a trapezoid alike?
A rectangle and a trapezoid are alike in that:both are polygonsboth have four sides (that is, both are quadrilaterals)both have four anglesboth have interior angles whose sum is 360°both have exterior angles whose sum is 360°both have at least one pair of parallel sidesthe area of each is (1/2 of the height) times (the sum of the bases)both can tesselateBy definition, a rectangle is NOT a trapezoid since a trapezoid can have ONLY one set of parallel sides and a rectangle always has two.
What is the formula for finding the area of the trapezoid?
The Trapezoid area formula would be (b1 + b2) H _________ 2 What this means is you add together both of the bases (top and bottom! and be sure to put b1 + b2 in parenthasis or you might loose points on a quiz!) then, the sum will be multiplied by the height. then once you have that, divide by 2.
What is the height of a trapizoid with an area of 9m2 and bases that measure 2.4m and 3.6m?
To find the height of a trapezoid with area 9m² and bases 2.4m and 3.6m, we use the formula for the area of a trapezoid: Area = 0.5 * (b1 + b2) * h. Given the bases b1 = 2.4m, b2 = 3.6m, and Area = 9m², we can solve for the height h: 9 = 0.5 * (2.4 + 3.6) * h. Simplifying gives: 9 = 0.5 * 6 * h, leading to h = 9 / 3 = 3m. Thus, the height of the trapezoid is 3m.
How is the formula for the area of trapezoid related to the formula for the area of a parallelogram?
They both use perpendicular height and are in square units. Area of a trapezoid = 0.5*(sum of parallel sides)*perpendicular height Area of a parallelogram = base*perpendicular height
What is the area of a trapezoid if the bases are 22 and 10 and the legs are 10?
Since the legs are both 10, it is an isosceles trapezium. Using Pythagoras's theorem, the height of the trapezium is 8 and so its area is 1/2*(22 + 10)*8 = 128 square units.
How is the formula for the area of a trapezoid related to the formula for a area of a parallelogram?
They both use perpendicular height and are in square units. Area of a trapezoid = 0.5*(sum of parallel sides)*perpendicular height Area of a parallelogram = base*perpendicular height
A trapezoid has an area of 45 cm2 The two bases are 6 cm and 12 cm What is the height of the trapezoid?
The area of a trapezoid is equal to one half the product of the length of its height and the sum of its bases. So we have: A = (1/2)(h)(B + b) substitute what you know into the formula 45 cm^2 = (1/2)(h)(12 cm + 6 cm) 45 cm^2 = (1/2)(h)(18 cm) 45 cm^2 = (h)(9 cm) divide by 9 cm to both sides 5 cm = h Thus, the height is 5 cm.
