No. The formula for the area of a rectangle, the easiest to measure, goes as follows goes as follows:
X=distance of side A
Y=distance of side B
A=area of figure
Now, the formula is:(X)(Y)=A
for other figures you convert them into
triangles where you can use (Base)(height) divided by 2=A
this is called triangulation.
Speed is equal to the magnitude of velocity almost always. Speed is total distance / total time no matter which way the distance goes. Velocity is the distance from a starting point divided by total time.
Yes.
average
correct
Miles measures distance. Square miles measures area. Therefore, you can not compare the two. It is like comparing feet and cups.
Average speed is equal to the total distance travelled divided by total time.
Speed is equal to the magnitude of velocity almost always. Speed is total distance / total time no matter which way the distance goes. Velocity is the distance from a starting point divided by total time.
Yes.
average
correct
No, it is not always true that the total distance is equal to the displacement. Total distance is the sum of all path lengths travelled, while displacement is the shortest distance between the initial and final positions. In some cases, these two values may be equal, but not always.
Miles measures distance. Square miles measures area. Therefore, you can not compare the two. It is like comparing feet and cups.
No, your total displacement (the straight line distance from start to finish, regardless of path taken) cannot be greater than your total distance (the sum of all the length of the path taken). Displacement can be shorter or equal to distance, but not greater.
Distance is equal to displacement when an object moves in a straight line without changing direction. In such cases, the magnitude of displacement is equal to the total distance traveled. Displacement is a vector quantity that takes into account both the distance traveled and the direction in which the object moved.
A body in simple harmonic motion with amplitude A will move a total distance fo 2A in a time equal to one period.
The area of a parallelogram is equal to the length of the base times the shortest distance to the opposite side.
The area under a force-distance graph represents the work done. It is equal to the force applied multiplied by the distance moved in the same direction as the force.