The question is rather simple, since you need an even number greater than 700 that is three digits we have a number that is of the form
7-even-even (odd + odd + even = even but 11 is of the form 2k+1 which is odd)
8-odd-even (odd +even+even = an even number)
902, 920 or 911 (this is because the sum of the digits is 11 and using 9 we would have 9 +X + Y = 11 which means that X + Y = 2 and we have a linear diophantene equation with the solutions (1,1), (2,0) (0,2)
for example 704 (7 + X + Y = 11 means X + Y = 4 so we have (2,2), (4,0) (0,4) ,(1,3) and (3,1)
Also,
803 because 8 + X + Y = 11 or X + Y = 3 and you would get (0,3) (1,2) (2,1) (3,0) as solutions.
Humans normally have ten fingers and ten toes, a total of twenty digits.
To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts. Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits. Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits. a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits. b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits. Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.
18.You can answer it easily by considering three places for three digits of the number.The hundreds place cannot take zero hence it can take 2 values.The next two places can take all the three digits.Hence the total number of ways is 2*3*3=18.
0 and 9 or, 0 and anything really.
Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678 The digits total 36. 36 is divisible by 9. So is 12,345,678.
Total number of digits = 5
Humans normally have ten fingers and ten toes, a total of twenty digits.
To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts. Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits. Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits. a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits. b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits. Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.
#include<stdio.h> main () { int number, last_digit, next_digit, total; printf ("Enter the number whose sum of digits is to be calculated: "); scanf ("%d", &number); last_digit = number%10; total = last_digit; next_digit = (number/10) % 10; total = total + next_digit; next_digit = (number/100) % 10; total = total + next_digit; next_digit = (number/1000) %10; total = total + next_digit; next_digit = (number/10000) %10; total = total + next_digit; printf ("The sum of the digits of the entered number is: %d", total); }
I/you/we am 49
18.You can answer it easily by considering three places for three digits of the number.The hundreds place cannot take zero hence it can take 2 values.The next two places can take all the three digits.Hence the total number of ways is 2*3*3=18.
The sum of your digits is the total number arrived at after adding two or more numbers.
0 and 9 or, 0 and anything really.
Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678 The digits total 36. 36 is divisible by 9. So is 12,345,678.
Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678 The digits total 36. 36 is divisible by 9. So is 12,345,678.
No.
It is 120 if the digits cannot be repeated.