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The question is rather simple, since you need an even number greater than 700 that is three digits we have a number that is of the form

7-even-even (odd + odd + even = even but 11 is of the form 2k+1 which is odd)
8-odd-even (odd +even+even = an even number)
902, 920 or 911 (this is because the sum of the digits is 11 and using 9 we would have 9 +X + Y = 11 which means that X + Y = 2 and we have a linear diophantene equation with the solutions (1,1), (2,0) (0,2)

for example 704 (7 + X + Y = 11 means X + Y = 4 so we have (2,2), (4,0) (0,4) ,(1,3) and (3,1)

Also,

803 because 8 + X + Y = 11 or X + Y = 3 and you would get (0,3) (1,2) (2,1) (3,0) as solutions.

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Q: Even 3-digit number greater than 700 whose digits total 11?
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Humans normally have ten fingers and ten toes, a total of twenty digits.


What is the total of digits used in numbers from 51 to 5001?

To find the total number of digits used in numbers from 51 to 5001, we can break it down into two parts. Numbers from 51 to 99: Each number in this range has 2 digits, so there are 49 numbers in total, resulting in 49 x 2 = 98 digits. Numbers from 100 to 5001: Each number in this range has 3, 4, or 5 digits. a. For numbers from 100 to 999, each number has 3 digits, so there are 900 numbers in total, resulting in 900 x 3 = 2700 digits. b. For numbers from 1000 to 5001, each number has 4 or 5 digits. There are 4002 numbers in total, and if we assume each has 4 digits, it would be 4002 x 4 = 16008 digits. Adding all these together, the total number of digits used in numbers from 51 to 5001 is 98 + 2700 + 16008 = 18706 digits.


How many 3digit numbers can be formed from digits320 with repetition?

18.You can answer it easily by considering three places for three digits of the number.The hundreds place cannot take zero hence it can take 2 values.The next two places can take all the three digits.Hence the total number of ways is 2*3*3=18.


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How can you divide any number by 9?

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Humans normally have ten fingers and ten toes, a total of twenty digits.


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