86 because you times -3 and 2 then you get -6. Then you times 10 and -8 and you get 80. Last thing is to add -6 and 80. You get 86.
For the person that answered with that, this is factoring! As in algebra!
-3x2+10x-8 -3*-8=24 6*4=24 6+4=10
-3x2+6x+4x-8
[3xx 2*3x] [2*2x 2*2*2]
-3x(x-2)+4(x-2)
(x-2)(-3x+4)
Answer: (x-2)(-3x+4) not 86...
simple mistake, whoever answered that simply thought it was arithmetic -3*2+10*-8.
(-3x + 4)(x - 2)
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
x^2 + 10x + 16 = (x + 8)(x + 2)
(x - 8)(x - 2)
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
-(x + 2)(3x + 4)
(-3x + 4)(x - 2)
3x2 - 10x - 8 = (3x + 2) (x - 4)
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored
x^2 + 10x + 16 = (x + 8)(x + 2)
(x - 8)(x - 2)
(2x - 1)(5x + 8)
3x2 + 10x - 8The auxiliary equation is 3x2 + 10x - 24 [because 8*3 = 24] Two factors of -24 which sum to 10 are 12 and -2. So the factorisation of the auxillary is (3x + 12)*(3x - 2) = 3*(x + 4)*(3x - 2) Dividing by the 3 used to create the auxiliary gives the solution as (x + 4)*(3x - 2).
-(3x - 4)(x - 2)
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)