-(3x+4)(x+2)
3x^(2)- 10x - 8 = 0 (3x + 2 )(x - 4 ) = 0 3x + 2 = 0 3x = -2 x = -2/3 & x - 4 = 0 x = 4
3x2 + 33x + 54 =3(x2 + 11x + 18) = 3(x + 9)(x + 2)
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
3x2-y=6 3x2-y=6
Yes. (Assuming that -3x2 is the best representation of 3x2 that this browser will allow.)
It is: (-3x-4)(x+2) when factored
-(3x - 4)(x - 2)
Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored
-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)
3x2 + 10x + 3 = (x + 3)(3x + 1).
3x2 + 36x + 81 = 3(x2 + 13x + 27)
If you mean: 27x2-90x+27 then divide all terms by 9 which is then 3x2-10x+3 And when factored it is: (3x-1)(x-3)
the answer is 60
[ x3 + 3x2 + 2x ] is a trinomial. It's factors are [ x, (x + 1), (x + 2) ] .
3x2+7-6 = (3x-2)(x+3) when factored
3x2 + 36x + 81 = 3(x2 + 12x + 27) = 3(x + 3)(x + 9), which are its prime factors; or, if you prefer, 3x2 + 36x + 81 = (3x + 9)(x + 9), which is also accurate. You may easily verify these results by multiplying back.
3x2 -12x+24=-10x-20-3x2+6