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Factor 2x squared plus 2x plus xy plus y?
4
How do you factor x squared plus xy?
Divide by 'x'; x2+xy/x = x(x+y)
What is xy minus 2x plus 4y minus 8?
(y-2) (x+4)
Factor xy plus 2x plus 4y plus 8?
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
What is the factor of 2x2-2x plus xy-y?
(x - 1)(2x + y)
How do you rewrite this equation so that y is a function of x 2x plus y equals 7?
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X
Factor completely xy - 2x plus 4y -8?
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
What is 2x-y8 where x6?
2x-y8 where x is 6: xy=8-2=6
How do you factor 2x2-xy-3y2?
(2x - 3y)(x + y)
Find the derivative of y x2 sin x 2xcos x - 2sin x?
y = (x^2)(sin x)(2x)(cos x) - 2sin xy' = [[(x^2)(sin x)][(2x)(cos x)]]' - (2sin x)'y' = [[(x^2)(sin x)]'[(2x)(cos x)] + [(2x)(cos x)]'[(x^2)(sin x)]]- (2sin x)'y' = [[(x^2)'(sin x) + (sin x)'(x^2)][(2x)(cos x)] + [(2x)'(cos x) + (cos x)'(2x)][(x^2)(sin x)] ] - 2(cos x)y' = [[(2x)(sin x )+ (cos x)(x^2)][(2x)(cos x)] + [2cos x - (sin x)(2x)][(x^2)(sin x)]] - 2(cos x)y' = (4x^2)(sin x cos x) + (2x^3)(cos x)^2 + (2x^2)(sin x cos x) - (2x^3)(sin x)^2 - 2cos xy' = (6x^2)(sin x cos x) + (2x^3)(cos x)^2 - (2x^3)(sin x)^2 - 2cos x (if you want, you can stop here, or you can continue)y' = (3x^2)(2sin x cos x) + (2x^3)[(cos x)^2 - (sin x)^2] - 2cos xy' = (3x^2)(sin 2x) + (2x^3)(cos 2x) - 2 cos xy' = (2x^3)(cos 2x) + (3x^2)(sin 2x) - 2 cos x
What is the answer to xy-x plus 2y-2?
0
Factor xy - 2x plus 4y - 8?
(x + 4)(y - 2)
