Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. I am, therefore, not sure that I am answering the question that you want answered! If so, please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals" etc.
Both sin4x and sin6x tend to 0 as x tends to and so their product must also tend to 0.
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
6x+13 is just 6x+13 you can not combine the terms because they are not like terms. ifyou make this expression equal a value... lets say 1 then you can find a value for "x" 6x+13=1 6x+13-13=1-13 6x=-12 x=-2
10
6x = 3/5 30x = 3 x = 3/30 x = 1/10
x=1.5 and y=6x so y=6(1.5) y=9
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals" etc. As it appears, you seem to be seeking the limit of sin(4x)*sin(6x) as x tends to 0. Both components of the product tend to 0 as x tens to 0 and so the limit is 0. Bit I suspect that is not the limit that you are looking for.
That means you must take the derivative of the derivative. In this case, you must use the product rule. y = 6x sin x y'= 6[x (sin x)' + (x)' sin x] = 6[x cos x + sin x] y'' = 6[x (cos x)' + (x)' cos x + cos x] = 6[x (-sin x) + cos x + cos x] = 6[-x sin x + 2 cos x]
4 sin(6x) cos(6x) is already a function of a single variable. The variable is ' x '.
6x and 5y
If 6x-2y=18 then -2y=-6x+18 and y=3x+9 so the gradient is 3
solve 6x - 9 = -3x + 36?
x2 - 6x + 5 = (x - 1)(x - 5)
The GCF is 3.
6x+13 is just 6x+13 you can not combine the terms because they are not like terms. ifyou make this expression equal a value... lets say 1 then you can find a value for "x" 6x+13=1 6x+13-13=1-13 6x=-12 x=-2
1242
y = - x2 +6x - 5.5