The given expression is not an equation because it has no equality sign
The given expression is not an equation because it has no equality sign
To determine which point lies on the graph of the equation (3x + 2y = 7x - 5), first, we can rewrite it in standard form. Rearranging gives (2y = 4x - 5) or (y = 2x - \frac{5}{2}). You can then test specific points (like integers) to see which satisfies this equation. For example, if you substitute (x = 2), then (y = 2(2) - \frac{5}{2} = 4 - 2.5 = 1.5), so the point (2, 1.5) lies on the graph.
If you mean: y = 3x+5 then it is a straight line equation that can be plotted on a graph whereas 3 is the slope and 5 is the y intercept
To find the point that lies on the line described by the equation ( y = 84(x - 5) ), you can choose any value for ( x ) and calculate the corresponding ( y ). For example, if you let ( x = 5 ), then ( y = 84(5 - 5) = 0 ). Thus, the point (5, 0) lies on the line. You can substitute other ( x ) values for additional points.
5
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
(6,2)
The given expression is not an equation because it has no equality sign
(5, -8)
79
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
To determine which point lies on the graph of the equation (3x + 2y = 7x - 5), first, we can rewrite it in standard form. Rearranging gives (2y = 4x - 5) or (y = 2x - \frac{5}{2}). You can then test specific points (like integers) to see which satisfies this equation. For example, if you substitute (x = 2), then (y = 2(2) - \frac{5}{2} = 4 - 2.5 = 1.5), so the point (2, 1.5) lies on the graph.
If you mean: y = 3x+5 then it is a straight line equation that can be plotted on a graph whereas 3 is the slope and 5 is the y intercept
To find the point that lies on the line described by the equation ( y = 84(x - 5) ), you can choose any value for ( x ) and calculate the corresponding ( y ). For example, if you let ( x = 5 ), then ( y = 84(5 - 5) = 0 ). Thus, the point (5, 0) lies on the line. You can substitute other ( x ) values for additional points.
5
Y=5