There is only one basic shape for an equilateral triangle. The area can only vary as the length of the sides vary.
In our example, the area of the equilateral triangle is 1/6 of the area of the regular hexagon
225(radical "3")/4
The area is: 15.6 (15.58846) square inches.
60 because there are 3 sides in a triangle and 60 x 3 =180, triangles are always equal to 180 * * * * * The above "answer" has nothing to do with the question! The area of an equilateral triangle with sides of s cm is s*sqrt(3)/4 square cm.
Given this area, the sides measure 52.92734 cm
There is only one basic shape for an equilateral triangle. The area can only vary as the length of the sides vary.
The area is 1.2 (1.16463) m2
If the sides are different lengths it ain't equilateral...
In our example, the area of the equilateral triangle is 1/6 of the area of the regular hexagon
Find the area of an equilateral triangle if its perimeter is 18 ft
225(radical "3")/4
It will be 9 times as large. And that will be true for any plane shape, not just an equilateral triangle.
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
Do you mean an equilateral triangle? Then if so then the formula for the area of any triangle: 0.5*a*b*sinC whereas a and b are the embraced sides of angle C And in the case of an equilateral triangle it is: 0.5*any side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find the altitude of the triangle then use: 0.5*base*height = area
27.713 square inches.
The area is: 15.6 (15.58846) square inches.