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The Euclidean distance is sqrt{[-10 - (-4)]2 + [6 - (-4)]2}
=sqrt{62 + 102} = sqrt(36 + 100} = sqrt(136) = 11.66 (to 2 dp)
There can be other metrics defined on the space - the Minkovsky, or Manhattan metric, is one where the distance is the sum of the steps in the two orthogonal directions required to go from one point to the other. In this case that would be 6 + 10 = 16 units. (The name comes from the grid-like pattern of the Manhattan roads.)
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What is the distance between the points (45) and (1013) on a coordinate plane?
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
What is the distance between the points (4 5) and (10 13) on a coordinate plane?
10 units
Find the distance between the two points -10 8 and -2 -7?
(-10--2)2+(8--7)2 = 289 and the square root of this is 17 Therefore the distance is 17 units in length.
What is the distance between the points -30 -10 and -30 18 in the xy plane?
18 - (-10) = 18 + 10 = 28 units.
Find the distance between these points A32 B910?
If the points are (3, 2) and (9, 10) then the distance works out as 10
Find the distance between the points-2 -10 and -8 -2?
10
Find the distance between the points -2 -10 and 10 6?
The sq.root of 122+162=20
Find the distance between the points A 9 3 and B 15 11?
10
What is the distance between the points (45) and (1013) on a coordinate plane?
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
What is the distance between the points (10 12) and (4 36)?
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
What is the distance between the points 4 5 and 10 13 on a coordinate plane?
The distance along a straight line is 10. Using the Pythagorean equation, c2 = a2 + b2 where the x change is 6 and the y change is 8, c2 = 62 + 82 = 36 + 64 = 100 c = [sqrt 100] = 10
What is the distance between the points -6-10 and 25?
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
What is the distance between the points (4 5) and (10 13) on a coordinate plane?
10 units
Find the distance between the two points -10 8 and -2 -7?
(-10--2)2+(8--7)2 = 289 and the square root of this is 17 Therefore the distance is 17 units in length.
Find the distance between points -6 1 and 10 -8?
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
