Pythagoras! x-axis difference is 7 units, y-axis difference is 7 units, so distance is sqrt(7^2 + 7^2) ie sqrt 98 = 9.9 to first significant figure.
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To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
the distance between two points is length
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Points: (2, 2) and (8, -6) Distance: 10
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
0 0
10
8.54
If the points are (3, 2) and (9, 10) then the distance works out as 10
To find the distance between two points on a graph, you can use the distance formula: √((x₂ - x₁)² + (y₂ - y₁)²). Plug in the coordinates of the two points to calculate the distance.
the distance between two points is length
The distance between the points of (4, 3) and (0, 3) is 4 units
11 points
Points: (-6, 1) and (-2, -2) Distance: 5 units
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Points: (2, 2) and (8, -6) Distance: 10
length