Pythagoras! x-axis difference is 7 units, y-axis difference is 7 units, so distance is sqrt(7^2 + 7^2) ie sqrt 98 = 9.9 to first significant figure.
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the distance between two points is length
Points: (2, 2) and (8, -6) Distance: 10
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
Points: (2, 1) and (14, 6) Distance: 13