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∙ 8y agoWithout an equality sign and not knowing the plus or minus values of some of the given terms it can't be considered to be a straight line equation.
In general parallel equations have the same slope but different y intercepts.
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∙ 8y agoi am cute
It has no equation as such because plotting the line on a grid will produce a vertical straight line parallel to the y axis.
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
Without an equality sign it is not an equation but when a straight line equation is parallel to another straight line the slope remains the same but the y intercept is different
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.
i am cute
It has no equation as such because plotting the line on a grid will produce a vertical straight line parallel to the y axis.
In 2-dimensional co-ordinate geometry, a line parallel to the y axis has the equation x = c where c is a constant.
5
find equation of the line. write equation in slope intercept form. (5,5) parallel line (3,13) and (12,13)
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
Without an equality sign it is not an equation but when a straight line equation is parallel to another straight line the slope remains the same but the y intercept is different
When the equation of a line is parallel to another line the slope remains the same but the y intercept changes
what
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.