yes, since according to the 68-95-99.7 rule, the area within 3 standard deviations is 99.7%
You want the area under the normal curve between z1 = (36-36.2)/3.7 and z2 = (37.5-36.2)/3.7 Using half tail tables (which give the probability (area under the normal curve) between the mean and z - the number of standard deviations from the mean of the value, negative just means it's to the left of the mean): z1 = (36 - 36.2) / 3.7 ≈ -0.0541 z2 = (37.5 - 36.2) / 3.7 ≈0.3514 → area between -0.0541 and 0.3515 standard deviations from the mean = 0.0199 + 0.1368 = 0.1567 = 15.67 %
That will be close to 90 percent of the population. Only about four percent would be above and below that area.
You cannot. In general there is no relationship between the area of a slab and its thickness.
It is z = -0.5244
z = 1.75
Above 1.96: 0.024998 = 2.5% below 1.96: 0.975002 = 97.5%
yes, since according to the 68-95-99.7 rule, the area within 3 standard deviations is 99.7%
It is 0.9955 of the total area.
95%
You want the area under the normal curve between z1 = (36-36.2)/3.7 and z2 = (37.5-36.2)/3.7 Using half tail tables (which give the probability (area under the normal curve) between the mean and z - the number of standard deviations from the mean of the value, negative just means it's to the left of the mean): z1 = (36 - 36.2) / 3.7 ≈ -0.0541 z2 = (37.5 - 36.2) / 3.7 ≈0.3514 → area between -0.0541 and 0.3515 standard deviations from the mean = 0.0199 + 0.1368 = 0.1567 = 15.67 %
That will be close to 90 percent of the population. Only about four percent would be above and below that area.
find the objects area first. Then put the objects' area into a fraction by smaller in numerator and larger in denominator then divide and put decimal into fraction or percent
95
Dr.Pepper
India is about seven percent of the size of all of Asia.
yoy surf over a lake between battle area and survival area