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let x be the sidelength of the square

by pythagoras' theorum:
x2+x2 = 122
2x2 = 144
x2 = 72
x = 6*(2)^0.5 [2^0.5 is the square root of 2]
x = 8.4852813742385702928 (20sf)

perimeter = 4x
perimeter = 33.941125496954281171(20sf)

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Q: Find the perimeter of a square with diagnal of length 12?
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