That's a vertical line; the slope is not defined.
First, you need to find the slope of the line we're given: 2x = 12y + 4 ∴ x = 6y + 3 ∴ 6y = x - 3 ∴ y = x/6 - 3 By that we can see that the slope of the line given is 1/6. To find the slope that is perpendicular, all you need to do reverse that fraction. Instead of 1/6, it would be 6/1. So the answer to your question is 6.
Slope of a line perpendicular to x-y=16
The equation for the slope of a line is y=mx+b
The graph of the equation [ x = -3 ] is a straight vertical line, passingthrough the point [ x = -3 ] on the x-axis. Its slope is infinite.
7X - 12Y = 96 - 12Y = - 7X + 96 Y = (7/12)X - 8 ============== m = 7/12 Y intercept = - 8
-6x + 12y = -102 -6x = -12y - 102 x = 2y + 17
5x=11y
That's a vertical line; the slope is not defined.
First, you need to find the slope of the line we're given: 2x = 12y + 4 ∴ x = 6y + 3 ∴ 6y = x - 3 ∴ y = x/6 - 3 By that we can see that the slope of the line given is 1/6. To find the slope that is perpendicular, all you need to do reverse that fraction. Instead of 1/6, it would be 6/1. So the answer to your question is 6.
Slope of a line perpendicular to x-y=16
The equation for the slope of a line is y=mx+b
The graph of the equation [ x = -3 ] is a straight vertical line, passingthrough the point [ x = -3 ] on the x-axis. Its slope is infinite.
x = -4y so 3x = -12y Substituting in the second equation, -12y + 2y = 20 or -10y = 20 ie y = -2 And then x = -4y implies that x = 8 Solution: x = 8, y = -2
It has infinite slope.
7x is still the slope, no matter what x equals.
5x=4012y=84124