The sum of the first 10 natural numbers is 51.
The sum of the first 10 natural numbers is 51, with an average of 5.1
Here it is: 500,001
#include<stdio.h> int main() { int limit,num,sum=0,i; printf("enter a number"); scanf("%d",&num); for(i=0;i<=num;i++) sum+=i; printf("%d",sum); return 0; }
To get the product, multiply the first number by the second. To get the sum, add the second number to the first. To get the difference, subtract the smaller number from the larger.
The sum of the first 10 natural numbers is 51.
Find the sum of the first hundred even natural number divisible by 5?
The sum of the first 100 natural numbers is 5,001.
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Write an. Algorthim. To. Find the. Sum. Of. First15 natural. Numbers
The sum of the first 10 natural numbers is 51, with an average of 5.1
Here it is: 500,001
Yes
Sum = Sum + first number Sum = Sum + second number Sum = Sum + third number Average = 1/3 x Sum
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Formula for sum of first natural number = n(n+1)/2 , here n=225 so, answer is 225(225+1)/2 = 25425