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The points at which the parabola intersects the x axis are 3-sqrt(10)/2 and 3+sqrt(10)/2. The X position of the vertex is in the middle, at 3. The y position, from there, is simply found by substituting 2 for x in the equation. As a result, the vertex is at (3, 5).

Q: Find the vertex of the parabola y equals -2x2 plus 12x - 13?

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The vertex has a minimum value of (-4, -11)

(-3, -5)

The vertex of the positive parabola turns at point (-2, -11)

It is a parabola with its vertex at the origin and the arms going upwards.

20 and the vertex of the parabola is at (3, 20)

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The vertex has a minimum value of (-4, -11)

The vertex of the positive parabola turns at point (-2, -11)

(-3, -5)

The minimum value of the parabola is at the point (-1/3, -4/3)

It is a parabola with its vertex at the origin and the arms going upwards.

20 and the vertex of the parabola is at (3, 20)

The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).

Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.

The given equation is not that of a parabola.

By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero

-2-5

The vertex is at (-1,0).