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What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
What is the vertex of the parabola y equals 2x squared plus 12x 13?
(-3, -5)
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
How does y equals 4x2 plus 21x look in a graph?
It is a parabola with its vertex at the origin and the arms going upwards.
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
What is the vertex of the parabola y equals 2x squared plus 12x 13?
(-3, -5)
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
What is the vertex of the parabola when y equals 3x squared plus 2x minus 1?
The minimum value of the parabola is at the point (-1/3, -4/3)
How does y equals 4x2 plus 21x look in a graph?
It is a parabola with its vertex at the origin and the arms going upwards.
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
What is y equals x2 plus 2x plus 1 on a graph?
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
What is the x coordinate of the vertex parabola defined by the following function 3x plus x plus 7x plus 4?
The given equation is not that of a parabola.
How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
Find the vertex of y equals x2 plus 10x plus 22?
-2-5
What is the vertex for the parabola y equals x squared plus 4x plus 5?
y = x^(2) + 4x + 5 Find the vertex , differentiate and equate to zero. dy/dx = 0 = 2x + 4 2x + 4 - 0 2x = -4 x = -2 To find if the vertex is at a max/min differentiate are second time. If the answer is positive(+)/Negative(-), then it is a minimum/maximum. Hence dy/dx = 2x + 4 d2y/dx2 = (+)2 Positive(+) so the parabola is at a minimum. at x = -2.
Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
