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Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2.

4 times the smallest is 8a-8

So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10

So, 6a-10 = 2*2a = 4a so that 2a = 10

So the integers are 8, 10 and 12.

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โˆ™ 2009-09-25 14:33:48
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Q: Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest the result is 8 more than twice the middle integer?
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