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Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest the result is 4 more than twice the middle integer?
Wiki User
∙ 8y ago
If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer.
Let the smallest integer be x, then the others are x + 2 and x+ 4.
Therefore
4x - (x + 4) = 2 (x + 2 ) + 4
Expanding, we get
4x -x -4 = 2x + 4 + 4
Gathering terms:
x = 12
Thus the three integers are 12, 14 and 16.
Wiki User
∙ 8y ago
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