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If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer.

Let the smallest integer be x, then the others are x + 2 and x+ 4.

Therefore

4x - (x + 4) = 2 (x + 2 ) + 4

Expanding, we get

4x -x -4 = 2x + 4 + 4

Gathering terms:

x = 12

Thus the three integers are 12, 14 and 16.

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Q: Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest the result is 4 more than twice the middle integer?

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