If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer.
Let the smallest integer be x, then the others are x + 2 and x+ 4.
Therefore
4x - (x + 4) = 2 (x + 2 ) + 4
Expanding, we get
4x -x -4 = 2x + 4 + 4
Gathering terms:
x = 12
Thus the three integers are 12, 14 and 16.
59,61,63,65 It is 59
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
The sum of three consecutive integers is -72
The first integer is 44.
There are not two consecutive odd integers. An integer is a whole number and consecutive is something that follows continuously/unbroken, logical sequence. All odd integers will have an even integer in between: 1, 2, 3, 4, 5...
The smallest is 121.
59,61,63,65 It is 59
Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.
consecutive integers
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
"Consecutive" integers are integers that have no other integer between them.
The sum of three consecutive integers is -72
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
1 is the smallest positive integer. But if you include negative integers, there is no smallest.
Let x equal the smallest integer. The sum will be 3x + 6
The first integer is 17.