If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer.
Let the smallest integer be x, then the others are x + 2 and x+ 4.
Therefore
4x - (x + 4) = 2 (x + 2 ) + 4
Expanding, we get
4x -x -4 = 2x + 4 + 4
Gathering terms:
x = 12
Thus the three integers are 12, 14 and 16.
59,61,63,65 It is 59
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
The sum of three consecutive integers is -72
There are not two consecutive odd integers. An integer is a whole number and consecutive is something that follows continuously/unbroken, logical sequence. All odd integers will have an even integer in between: 1, 2, 3, 4, 5...
The two integers are 6 and 7.
The smallest is 121.
59,61,63,65 It is 59
Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.
consecutive integers
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
"Consecutive" integers are integers that have no other integer between them.
The sum of three consecutive integers is -72
Yes, when an integer is subtracted from another integer, the result is still an integer. This is due to the closure property of integers, which states that the set of integers is closed under subtraction. Therefore, any operation involving two integers, such as subtraction, will yield another integer.
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
1 is the smallest positive integer. But if you include negative integers, there is no smallest.
Let x equal the smallest integer. The sum will be 3x + 6