The language of the question is too ambiguous. In mathematics, we use precise language to avoid this problem. point a is 40 metres from the base of building B the angle of elevation to the top of building C is 51 degree and to the top of the flagpole D on top of building is 56 dedree
To find the height of the flagpole, you can use the concept of similar triangles. The ratio of the height of the flagpole to the length of its shadow should equal the ratio of the height of the meter stick (1 meter) to its shadow (1.4 meters). Therefore, the height of the flagpole can be calculated as follows: [ \text{Height of flagpole} = \frac{7.7 , \text{m}}{1.4 , \text{m}} \times 1 , \text{m} \approx 5.5 , \text{m}. ] Thus, the flagpole is approximately 5.5 meters tall.
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
You can then work out the angle of elevation ------------- What is it you want to find out? In any case, you would have to look up the latitude of each place, and perhaps also the time of year. It might be easiest if it were the spring or fall equinox.
To calculate the height of the building, we can use the tangent function, which relates the angle of elevation to the opposite side (height of the building) and the adjacent side (distance from the point to the building). If we denote the height of the building as ( h ) and the distance from point M to the building as ( d ), we have: [ \tan(30^\circ) = \frac{h}{d} ] Since (\tan(30^\circ) = \frac{1}{\sqrt{3}}), we can rearrange the equation to find the height: [ h = d \cdot \frac{1}{\sqrt{3}} \approx 0.577 d ] Thus, the height of the building is approximately 0.577 times the distance from point M to the building.
6 metres!
The flagpole is 15.92 metres, approx.
If you mean the height of the building then it works out as 466.5063509 feet
The answer is 0.33
If you also know its shadow then you can work out the angle of elevation
Tangent(theta) is sine over cosine, or y over x. x is 120. Theta is 32 and 37. y1 is height of cliff, and y2 is height of cliff plus flagpole.Tan(32) = y1 / 120, so y1 = 120 tan(32) = 75.Tan(37) = y2 / 120, so y2 = 120 tan(37) = 90.Height of flagpole is y2 - y1 = 90 - 75 = 15.All results rounded to nearest integer.
Monument Park at Yankee Stadium was relocated to the new Yankee Stadium. The new flagpole has a height of 60 feet.
Angle of elevation: tangent angle = opposite/adjacent and by rearranging the given formula will help to solve the problem
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
You can then work out the angle of elevation ------------- What is it you want to find out? In any case, you would have to look up the latitude of each place, and perhaps also the time of year. It might be easiest if it were the spring or fall equinox.
It is: tan(65)*200 = 429 meters rounded
6 metres!
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)