If you are talking about functions in 2-dimensional space, that is, functions of the sort y = f(x), then, by definition, none can be positive in the third quadrant where y is always negative. If you are talking about functions in 3-dimensional space, ie functions of the kind z = f(x,y), then for the third quadrant in terms of x and y (x<0 and y<0), there are infinitely many functions for which z > 0.
1.4 Classification Of FunctionsAnalytically represented functions are either Elementary or Non-elementary.The basic elementary functions are :1) Power function :y = xm , m ÎR2) Exponential function :y = ax , a > 0 but a ¹ 13) Logarithmic function :y = log ax , a > 0, a ¹ 1 and x > 04) Trigonometric functions :y = sin x, y = cos x, y = tan x,y = csc x, y = sec x and y = cot x5) Inverse trigonometric functionsy = sin-1 x, y = cos-1x, y = tan-1x,OR y = cot-1x, y = cosec-1x, y = sec-1x.y = arc sin x, y = arc cos x, y = arc tan xy = arc cot x, y = arc csc x and y = arc sec x
the x is dependent and the y is independent and the x numbers cant repeat themself and yes they do have intercepts
If you reflect a function across the line y=x, you will have a graph of the inverse. For trigonometric problems: y = sin(x) has the inverse x=sin(y) or y = sin-1(x)
You can use intercept form to graph and write quadratic functions. y=a(x-p)(x-q) You can also use intercept form to graph and write cubic functions. y=a(x-p)(x-q)(x-r)
y = x2 or y = x +2, both are functions
If you are talking about functions in 2-dimensional space, that is, functions of the sort y = f(x), then, by definition, none can be positive in the third quadrant where y is always negative. If you are talking about functions in 3-dimensional space, ie functions of the kind z = f(x,y), then for the third quadrant in terms of x and y (x<0 and y<0), there are infinitely many functions for which z > 0.
1.4 Classification Of FunctionsAnalytically represented functions are either Elementary or Non-elementary.The basic elementary functions are :1) Power function :y = xm , m ÎR2) Exponential function :y = ax , a > 0 but a ¹ 13) Logarithmic function :y = log ax , a > 0, a ¹ 1 and x > 04) Trigonometric functions :y = sin x, y = cos x, y = tan x,y = csc x, y = sec x and y = cot x5) Inverse trigonometric functionsy = sin-1 x, y = cos-1x, y = tan-1x,OR y = cot-1x, y = cosec-1x, y = sec-1x.y = arc sin x, y = arc cos x, y = arc tan xy = arc cot x, y = arc csc x and y = arc sec x
The period of the function y= tan(x) is pie The periods of the functions y= cos(x) and y= sin(x) is 2pie
The period of the function y= tan(x) is pie The periods of the functions y= cos(x) and y= sin(x) is 2pie
1/x = y x = 1/y
symmetric about the y-axis symmetric about the x-axis symmetric about the line y=x symmetric about the line y+x=0
the x is dependent and the y is independent and the x numbers cant repeat themself and yes they do have intercepts
If f(x)=y, then the inverse function solves for y when x=f(y). You may have to restrict the domain for the inverse function to be a function. Use this concept when finding the inverse of hyperbolic functions.
y = X^2 Is this what you mean? functions are y values when x = 1; y =1 when x = -1; y = 1 when x = 2; y = 4 when x = -2; y = 4 when x = 3; y = 9 when x = -3; y = 9 get it? A upward opening parabola with its vertex at the origin.
If you reflect a function across the line y=x, you will have a graph of the inverse. For trigonometric problems: y = sin(x) has the inverse x=sin(y) or y = sin-1(x)
y = x² - 2x - 8 Swap x and y to find the inverse: x = y² - 2y - 8 Now get y by itself: y² - 2y = x + 8 (Complete the square): y² - 2y + 1 = x + 9 (y - 1)² = x + 9 y - 1 = ±√(x + 9) y = 1 ±√(x + 9) Then there are two functions: f(x) = 1 - √(x + 9) and f(x) = 1 + √(x + 9) but an inverse can only be one function. The functions above are a mirror image of the original function, but it is not an inverse (graph these functions). There is no inverse. Everything above is completely wrong. This is the inverse: (x+8)/2 I don't know where the x² came from in the first answer, but to work out the question as asked: if y=2x-8 y+8 = 2x (y+8)/2 = x so, as the above answer stated, (x+8)/2 is the answer.