There is not much that can be done by way of simplification. Suppose arccot(y) = tan(x) then y = cot[tan(x)] = 1/tan(tan(x)) Now cot is NOT the inverse of tan, but its reciprocal. So the expression in the first of above equation cannot be simplified further. Similarly tan[tan(x)] is NOT tan(x)*tan(x) = tan2(x)
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
Yes. Both expressions are the same.
If the angle is x radians, then tan(x) = 1/20 = 0.05 So x = tan-1(0.05) = 0.04996 radians = 2.86 degrees (approx)
For a right angle triangle the trigonometrical ration is: tangent = opposite/adjacent
The period of the function y= tan(x) is pie The periods of the functions y= cos(x) and y= sin(x) is 2pie
You find the smallest positive value y such that tan(x + y) = tan(x) for all x.
1 (sec x)(sin x /tan x = (1/cos x)(sin x)/tan x = (sin x/cos x)/tan x) = tan x/tan x = 1
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
It is used when a function takes the same values after some fixed interval, and multiples of that interval. For example, tan(x) = tax(x + 180) = tan(x + 360) = tan(x + n*180) for all integer values of n. So tan is said to be periodic, with period 180 degrees (or π radians).
tan(-x) = -tan(x)
There is not much that can be done by way of simplification. Suppose arccot(y) = tan(x) then y = cot[tan(x)] = 1/tan(tan(x)) Now cot is NOT the inverse of tan, but its reciprocal. So the expression in the first of above equation cannot be simplified further. Similarly tan[tan(x)] is NOT tan(x)*tan(x) = tan2(x)
No. Tan(x)=Sin(x)/Cos(x) Sin(x)Tan(x)=Sin2(x)/Cos(x) Cos(x)Tan(x)=Sin(x)
y = -5tan(x) can also be written y/(-5) = tan(x). In other words, the -5 just changes the y values and the orientation of the graph (it flips tan(x) over the y axis and stretches the graph up and down). So -5tan(x), like tan(x), has a period of pi. This is because tan is the y value divided by the x value at any given point on the unit circle. At 0 degrees, x is at one and y is at zero, so tan0o = 0. As we travel counterclockwise around the unit circle, tan is next equal to zero when x is equal to zero. This occurs halfway around the circle at 180o, or (in radians) pi.
The period of the tangent function is PI. The period of y= tan(2x) is PI over the coefficient of x = PI/2
tan x
tan(x)*csc(x) = sec(x)