A cube is either a three dimensional figure or a number multiplied by itself and then again.
A square is either a two dimensional figure or a number multiplied by itself.
The Pythagorean Theorem states that the square od the hypotenuse of a right angled triangle is equal to the squares on the other two sides
With the above in mind your question your question is meaningless
By using Pythagoras' theorem.
Say you know the surface area of said cube is 450. cubes have six sides, so you need to find the area of one of them by doing 450/6 = 75. Think about 2d geometry. If you have a rectangle, how do you find it's diagonal? Using the Pythagorean theorem 'a' squared plus 'b' squared equals 'c' squared (keep in mind a + b doesn't equal c). so to get the interior diagonal, you need the diagonal of one of the faces and the length of a side. then re-use pythagorean to get it.
12 inches = 1 foot. 240 inches = 20 feet. Use Pythagoras' theorem to find the diagonal of one of the faces of the cube. 2402+2402 = 115200. The square root of 115200 is 339.411255 Therefore the diagonal of the cube is 339.411255 inches or 339 inches correct to three significant figures Incidentally, by using the above answer and Pythagoras' theorem we can also work out the length of the longest internal diagonal within the cube which works out exactly as 340 inches.
A cube is a three-dimensional square. One common cube that you have seen is a pair of dice.
It is s*√3, easily proved using Pythagoras's theorem.
You can use pythagorean theorem twice to find the diagonal of a cube
Yes Pythagoras' theorem can be used to find the interior diagonal of a cube for example.
find the cube root of 125(which is 5) is the length of one side do Pythagorean theorem to find the diagonal 5squared plus 5 squared=50 square root of 50=7.07106781 is diagonal
If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s
26, known as Fermat's Sandwich Theorem.
By using Pythagoras' theorem.
Pythagoras' theorem proves that if you draw a square on the longest side (the hypotenuse) of a right-angled triangle, its area is the same as the areas of the squares drawn on the two shorter sides, added together. See 'Pythagoras' theorem' under 'Sources and related links' below.Pythagoras' theorem holds for any right-angled triangle. But of special interest to Fermat were right-angled triangles where all the three sides were whole number lengths. These special lengths are known as Pythagorean triples.Here are some Pythagorean triples:-(3,4,5) (5, 12, 13) (7, 24, 25) (8, 15, 17)In each case, the square of each of the smaller numbers is equal to the square of the largest number.Fermat said that if instead of constructing squares (two dimensional figures) on the sides of right-angled triangles, you constructed cubes (three dimensional analogs of squares), or hypercubes (four dimensional analogs) or higher dimensional cube-analogs, there are no equivalents to the Pythagorean triples. In other words, there are no whole number values for 3, 4 or more dimensional analogs of the square.
Say you know the surface area of said cube is 450. cubes have six sides, so you need to find the area of one of them by doing 450/6 = 75. Think about 2d geometry. If you have a rectangle, how do you find it's diagonal? Using the Pythagorean theorem 'a' squared plus 'b' squared equals 'c' squared (keep in mind a + b doesn't equal c). so to get the interior diagonal, you need the diagonal of one of the faces and the length of a side. then re-use pythagorean to get it.
12 inches = 1 foot. 240 inches = 20 feet. Use Pythagoras' theorem to find the diagonal of one of the faces of the cube. 2402+2402 = 115200. The square root of 115200 is 339.411255 Therefore the diagonal of the cube is 339.411255 inches or 339 inches correct to three significant figures Incidentally, by using the above answer and Pythagoras' theorem we can also work out the length of the longest internal diagonal within the cube which works out exactly as 340 inches.
A cube is a three-dimensional square. One common cube that you have seen is a pair of dice.
It is s*√3, easily proved using Pythagoras's theorem.
This is a theorem by Fermat which states that 26 is the only positive integer number "sandwiched" between a cube (27=3^3) and a perfect square (25=5^2). The proof is elementary in number theory.