What is the correct classification of the system of equations below?x + 6y = 8y - 2x = 2
There is only one equation, so it's not a system of equations.
10
x = -3/5 and y = -24/5
slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
What is the correct classification of the system of equations below?x + 6y = 8y - 2x = 2
There is only one equation, so it's not a system of equations.
10
You cannot change two existing, completed equations so that they are equal to each other. However, when working with two equations, you may set them equal to each other to solve a system of equations. An example is the system of 2x+5y=103x-5p=10 You may now combine the two, as they both are equal to ten. This results in the eqation of 2x+5y=3x-5p You may simplify this to 5y=x-5p This brings you one step closer to solving, and one may complete the system with some additional information.
Without any equality signs the given expressions can't be considered as equations.
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
x = -3/5 and y = -24/5
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
If you mean: 6x-3y = -33 and 2x+y = -1 Then solving the simultaneous equations by substitution: x = -3 and y = 5
slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form
y= 3x - 4 y= -2x + 1 Since both equations are equal to y, it is possible to set both equations equal to each other: 3x - 4 = -2x + 1 Now, move the x variables to one side and the numbers to the other. Add 2x to both sides: 5x - 4 = 1 Add 4 to both sides: 5x = 5 Divide both sides by 5: x = 1