0
What else can I help you with?
Three consecutive odd integers that have a sum of 123?
123/3 = 41 so integers are 39, 41 and 43
Ind three consecutive odd integers that have a sum of 123?
x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43
Can you easily separate numbers divisible by 3?
Yes, you can easily determine if a number is divisible by 3 by checking if the sum of its digits is divisible by 3. For example, for the number 123, the sum of the digits is 1 + 2 + 3 = 6, which is divisible by 3, so 123 is also divisible by 3. This rule makes it straightforward to identify multiples of 3.
What is the sum of three consecutive integers is 126 so what are the integers?
:/ We can write it this way: x - 1 + x + x + 1 = 126. 1s cancel out, so we get 3x = 126. 126/3 = 42. Answer: 41, 42, 43.
What are three consecutive odd integers that have a sum of 123?
39, 41, 43 Let x represent the smallest of these numbers. From the problem, we know x+(x+2)+(x+4)=123 Solving for x: 3x+6=123 3x=117 x=117/3=39 So our integers are: 39, 41, 43
Three consecutive odd integers that have a sum of 123?
123/3 = 41 so integers are 39, 41 and 43
What two numbers have the sum of 123 but the difference of 7?
Suppose the smaller number is x, then the bigger number is x+7 Their sum is 123 ie x + (x+7) = 123 or 2x + 7 = 123 or 2x = 123 - 7 = 116 so that x = 58 and then x+7 = 65 The two numbers are 58 and 65
What is the average of 44 and 123?
E = Sum(i1, i2, .. in) / N So 44 + 123 = 167, N = 2 which make E = 83.5 or "average" of the values.
Ind three consecutive odd integers that have a sum of 123?
x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43
AS 675 is related to 929 in the same way 123 is related to what?
675:929::123:___ SOLUTION : Sum Of Digits in 675 is 6+7+5 = 18 Sum Of Digits in 929 is 9+2+9 = 20 Therefore, difference between them is 2 Sum Of Digits in 123 is 1+2+3 = 6 and sum of digits in 242 is 2+4+2 is 8 Therefore, difference is same So, the answer is 242
What are 5 odd number whose sum is from1 to 19?
There are many answers: if numbers can be repeated-1)all '1s' and all '3s' 2)4'1s' and so on....
How many number 1s has dizzee rascal had?
5 number 1s so far
How do you make hacker in doodle Devil?
You combine life & internet so in a sum formation (Internet + life = cyberspace)
Can you easily separate numbers divisible by 3?
Yes, you can easily determine if a number is divisible by 3 by checking if the sum of its digits is divisible by 3. For example, for the number 123, the sum of the digits is 1 + 2 + 3 = 6, which is divisible by 3, so 123 is also divisible by 3. This rule makes it straightforward to identify multiples of 3.
The sum of the first 5 terms of an arithmetic series is 85. The sum of the first 6 terms is 123. Determine the first four terms of the series.?
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
What is the sum of three consecutive integers is 126 so what are the integers?
:/ We can write it this way: x - 1 + x + x + 1 = 126. 1s cancel out, so we get 3x = 126. 126/3 = 42. Answer: 41, 42, 43.
One number is 8 more than twice the second number The sum of the numbers is 123 Find the numbers?
Let a be the first number and b the second number then, (1) a = 8 + 2b and (2) a + b =123 From (2) a = 123 - b substituting for a in (1) gives :- 123 - b = 8 + 2b , 3b = 115, b = 115/3 = 38⅓. and substituting for this in (2) gives :- a + 38⅓ = 123, a = 123 - 38⅓ = 84⅔. So, a = 84⅔ and b = 38⅓
