You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
Use the following formula: an = a1 + (n - 1)d, where a1 = the first term n = the n th term (general term) d = common difference (which is constant between terms) Since we need to find the 14 th term, we can write: a1 = 100 n = 14 d = -4 an = a1 + (n - 1)d a14 = 100 + (14 - 1)(-4) a14 = 100 + (13)(-4) a14 = 100 - 52 a14 = 48 Thus, the 14 th term is 48.
4
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Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
To find the sum of the first 100 positive multiples of 4, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, a1 = 4, an = 4*100 = 400, and n = 100. Plugging these values into the formula, we get: Sn = 100/2 * (4 + 400) = 50 * 404 = 20,200. Therefore, the sum of the first 100 positive multiples of 4 is 20,200.
You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
Use the following formula: an = a1 + (n - 1)d, where a1 = the first term n = the n th term (general term) d = common difference (which is constant between terms) Since we need to find the 14 th term, we can write: a1 = 100 n = 14 d = -4 an = a1 + (n - 1)d a14 = 100 + (14 - 1)(-4) a14 = 100 + (13)(-4) a14 = 100 - 52 a14 = 48 Thus, the 14 th term is 48.
answer:4
77 / 7 - 777 / 7 - 777 / 7 - 777 / 7 - 7
4
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=IF(A1>4,150,75) In this case if A1 is 4, then 75 will show. If you want 150 to show when A1 is 4 then the formula would be: =IF(A1>=4,150,75)
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
4 times with a remainder of 3
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.