16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
3x2-24x-48 is not factorable.
(3x-12)(x-4)
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
No real roots.
3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
3x2-24x-48 is not factorable.
(3x-12)(x-4)
By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
3x2=6+38=44
-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
6x(3x2 - x + 4)
GCF = 12x.24x = 2(12x)36x3 = 3x2(12x)