Q: How can you solve 3x2 plus 24x equals 0?

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16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16

3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x

3x2-24x-48 is not factorable.

(3x-12)(x-4)

Vertical line of symmetry cuts through x = -4 - (sqrt of 3)

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No real roots.

3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4

16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16

3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x

3x2-24x-48 is not factorable.

(3x-12)(x-4)

By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32

Vertical line of symmetry cuts through x = -4 - (sqrt of 3)

3x2=6+38=44

-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3

6x(3x2 - x + 4)

GCF = 12x.24x = 2(12x)36x3 = 3x2(12x)