How can you solve 3x2 plus 24x equals 0?

Answer 1

3x^(2) + 24x = 0

Divide by '3'

x^(2) + 8 = 0

x^(2) = - 8

x = sqrt(-8) Yjis is NOT resolved as you cannot take the squate root of a negative number, without going into IMAGINARY numbers.

x = sqrt( -1 X 8)

x = sqrt(-1) X sqrt(8)

x= sqrt(-1) X 2sqrt(2)

Sqrt(-1) is shown as 'i' ( small/lower case 'i' , algebraically).

Hence

x = 2sqrt(2) i

Answer 2

x=-.25.