Using algebra to determine if two lines are perpendicular to one another we first must determine each line's slope. Select two known points on each line to determine the slope for the line. The Point-slope form of a linear equation is (Y1-Y2) = m(X1-X2). Therefore The slope m = (Y1-Y2)/(X1-X2) We will use these points to generate the slope equation. Line A Line B Point 1 Point 2 Point 1 Point 2 X1,Y1 X2,Y2 A1,B1 A2,B2 If the product of the slopes of two lines = -1 then the two lines are perpendicular. Using the point slope form above the equation would look like this: [(Y1-Y2)/(X1-X2)] X [(A1-A2)/(B1-B2)] = m(line A) X m(line B) Example Line A Line B Point 1 Point 2 Point 1 Point 2 0,0 3,3 3,-3 0,0 Using the above formula [(0-3)/(0-3)] X [(3-0)/(-3-0)] = [-3/-3] X [3/-3] = 1 x -1 = -1 These two lines are perpendicular.
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In a way yes, Algebra 2 is essential in order for you to comprehend topics which will be in algebra. Such as finding the slope of perpendicular lines and parallel lines, those topics are presented to you in Algebra 2 and if you understand them at least 45% then by the time you get to college algebra that knowledge will be reinforced
You would use this: ┴
These lines are perpendicular: _|
perpendicular.
Lines that aren't perpendicular