6 triangles
In a regular hexagon in which the angles are congruent you can use a formula. ((6-2)*180)/6 120 degrees. The reason this works is that you can draw 4 diagonals inside the hexagon and triangles have 180 degrees each.
Divide the rectangle in two triangles and then use the pythagorean theorem to find the remaining sides.
To calculate the area of a regular hexagon, you can use the formula: Area = (3√3 × side length²)/2. Substituting the value of the side length given, the area of a hexagon with a side length of 10 is (3√3 × 10²)/2 = 150√3. Therefore, the area is approximately 259.81 square units.
Select any one of the vertices and draw all the diagonals from that vertex. This will divide the polygon (with n sides) into n-2 triangles. Use the coordinates of the vertices of each triangle to calculate its area, and then add the areas of these triangles together.
If you Google "area of a hexagon," you'll find quite a few websites with illustrations that will explain this better than I can without them. If you draw three diagonals from opposite corners of the hexagon, you will notice that the hexagon has been divided into six equilateral triangles. If you then draw six lines from the center to the midpoint of each side, you will have created twelve equal right triangles and can find the area of each by taking half of the base (which is half of a side) times the height. Multiply that by 12 and you have the area of the hexagon. The height of each triangle is the line you drew from the center to the middle of the side. This is known as an "apothem."
6 triangles
use 4 triangles, make 2 trapezoids then put them into a hexagon
Triangles you use : (base x perpendicular height) divided by 2. Parallelogram: you need to find the area of one of the side triangles, then double it (because there's two of them). Then find the area of the square in the middle, and add this to the area of the two triangles.
The area is about 2338.27 square units, from the formulaA = 3/2 (sqrt 3) s2 or about 2.598 s2--Let's draw a segment from the center of the hexagon to the middle of a side. This segment is called the apothem. Then use the 30-60-90 triangle rule. If half of a side is 15, that means the apothem is 15√3.If we divide the hexagon into equilateral triangles, we get 6 equilateral triangles.So if we find the area for one of these triangles and multiply it by 6, we get the area of the hexagon. The area of a triangle is found by 1/2(b*h). The apothem is your height for the triangles. So plug the numbers in: 1/2(30*15√3). Solve: 1/2(779.4228) = 389.7114. This is the area of one triangle. Now we multiply by 6, and this becomes: 2338.2686
We don't need the measure of the radius since we know the measure length of the side and of the apothem, which we use to find the area of one of the triangles that are formed by connecting the center with the vertices of the hexagon. So, A = 6[(1/2)(11 x 9)] = 297 m2
In a regular hexagon in which the angles are congruent you can use a formula. ((6-2)*180)/6 120 degrees. The reason this works is that you can draw 4 diagonals inside the hexagon and triangles have 180 degrees each.
Divide the rectangle in two triangles and then use the pythagorean theorem to find the remaining sides.
All you have to use is the five triangles. The two large triangles make a square in the middle, the two small triangles make a large triangle on one side and the middle triangle on the other side.
You would have to use a couple of formulas to do this. It would basically be 374.4 cm in area but first you would have to find the base and the height.
To calculate the area of a regular hexagon, you can use the formula: Area = (3√3 × side length²)/2. Substituting the value of the side length given, the area of a hexagon with a side length of 10 is (3√3 × 10²)/2 = 150√3. Therefore, the area is approximately 259.81 square units.
If you draw your triangles using the centre of the circle as one vertex and two more on the circumference, the area of the circle is approximately equal to the sum of the areas of the triangles; the smaller you make the triangles, the more accurate your result will be.